The quadratic equation that models the height of the rocket after t seconds is:
s(t) = -4.9t² + 39.2t.
<h3>What is the quadratic function for a projectile's height?</h3>
Considering the height in meters, the equation is given by:
s(t) = -4.9t² + v(0)t + h(0)
In which:
- v(0) is the initial velocity, in m/s.
- h(0) is the initial height, in m.
In this problem, we have that v(0) = 39.2, h(0) = 0, hence the equation is:
s(t) = -4.9t² + 39.2t.
More can be learned about quadratic functions at brainly.com/question/24737967
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Answer: 8/5
Step-by-step explanation: 1x5+3=8/5
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Answer:
4/992 = 0.00403225806
Step-by-step explanation:
I hope this helps!!
<span>5(2x - 7)
= 10x - 35
answer
</span><span>E. 10x - 35</span>
Answer:
<h2>For the first triangle, <u>x equals 22cm.</u></h2>
Here's how:-
x is the altitude or height of the triangle. To find it, we can use the Pythagoras theorem:-
The base is 120cm and the hypotenuse is 122cm
Putting this in the equation, we get:-
= 484
altitude = 
<h3>altitude = 22cm</h3><h2><u>So, x = 22cm</u></h2>
