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SVEN [57.7K]
3 years ago
15

If the radius of a circle is 3 meters, how long is the arc subtended by an angle measuring 30°?

Mathematics
1 answer:
FromTheMoon [43]3 years ago
3 0
Circumference of entire circle = 2 * PI * radius
2 * PI * 3 = <span> <span> <span> 18.8</span></span></span>5 meters
a 30 degree arc is (30/360) or 1/12 of a circle.
So the arc equals (18.85 meters / 12) or <span> <span> <span> 1.57</span></span></span> meters.


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igor_vitrenko [27]

Answer:

24

Step-by-step explanation:

            Problems at start =                 32

   -Problems done Friday = ¼ × 32 =  <u>  8</u>

Problems still to be done =                 24

Andrea had to do 24 problems on Saturday to complete the homework.

6 0
3 years ago
Find the sum of the summation of 3 i minus 15, from i equals 2 to 7.
Mrac [35]
The summation symbol means we use the variable i in the equation from the given range. In this case, we are given with the equation 3 i - 15 and i ranges from 2 to 7. The summation using simply the calculator is equal to -9. The answer to this problem is -9.
3 0
3 years ago
Read 2 more answers
4(2x+8)=10x+2-2x+30 what is x?
Anastaziya [24]

Let's solve your equation step-by-step.

4(2x+8)=10x+2−2x+30

Step 1: Simplify both sides of the equation.

4(2x+8)=10x+2−2x+30

(4)(2x)+(4)(8)=10x+2+−2x+30(Distribute)

8x+32=10x+2+−2x+30

8x+32=(10x+−2x)+(2+30)(Combine Like Terms)

8x+32=8x+32

8x+32=8x+32

Step 2: Subtract 8x from both sides.

8x+32−8x=8x+32−8x

32=32

Step 3: Subtract 32 from both sides.

32−32=32−32

0=0

Answer:

All real numbers are solutions.

5 0
2 years ago
How to do this in a 6th grade way
il63 [147K]

Answer:

4 2/3 - 1 2/3 and just keep doing that until you get to 0 it would take 3 days

Step-by-step explanation:

4 2/3 - 1 2/3=3

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6 0
2 years ago
In the rolling of two fair dice calculate the following: P(Sum of the two dice is 7) = ______
vesna_86 [32]

Answer:

P(Sum of the two dice is 7) = 6/36

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

A fair dice can have any value between 1 and 6 with equal probability. There are two fair dices, so we have the following possible outcomes.

Possible outcomes

(first rolling, second rolling)

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)

(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)

(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)

(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)

(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)

(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

There are 36 possible outcomes.

Desired outcomes

Sum is 7, so

(1,6), (6,1), (5,2), (2,5), (3,4), (4,3).

There are 6 desired outcomes, that is, the number of outcomes in which the sum of the two dice is 7.

Answer

P(Sum of the two dice is 7) = 6/36

7 0
3 years ago
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