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SVEN [57.7K]
3 years ago
15

If the radius of a circle is 3 meters, how long is the arc subtended by an angle measuring 30°?

Mathematics
1 answer:
FromTheMoon [43]3 years ago
3 0
Circumference of entire circle = 2 * PI * radius
2 * PI * 3 = <span> <span> <span> 18.8</span></span></span>5 meters
a 30 degree arc is (30/360) or 1/12 of a circle.
So the arc equals (18.85 meters / 12) or <span> <span> <span> 1.57</span></span></span> meters.


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Find the length of the third side. If necessary, round to the nearest tenth.
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Step-by-step explanation:

use formula a^2 + b^2 = c^2

a^2 + 12^2 = 13^2

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You and your friends have decided to camp for a night. Your friend claims the area of his tent is 408 m2. Work out the area of h
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We know that
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Read 2 more answers
What are the possible rational roots of the polynomial equation?<br><br> 0=2x7+3x5−9x2+6
RoseWind [281]

Answer: \pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0

Where:

- The coefficients are integers.

- a_n is the leading coeffcient (a_n\neq 0)

- a_0 is the constant term a_0\neq 0

Every rational root of the polynomial is in the form:

\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}

For the case of the given polynomial:

2x^7+3x^5-9x^2+6=0

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

 Then, by Rational Roots Test we get the possible rational roots of this polynomial:

\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

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