Answer:
The rate at which the distance from the plane to the station is increasing is 331 miles per hour.
Step-by-step explanation:
We can find the rate at which the distance from the plane to the station is increasing by imaging the formation of a right triangle with the following dimensions:
a: is one side of the triangle = altitude of the plane = 3 miles
b: is the other side of the triangle = the distance traveled by the plane when it is 4 miles away from the station and an altitude of 3 miles
h: is the hypotenuse of the triangle = distance between the plane and the station = 4 miles
First, we need to find b:
(1)

Now, to find the rate we need to find the derivative of equation (1) with respect to time:
Since "da/dt" is constant (the altitude of the plane does not change with time), we have:
And knowing that the plane is moving at a speed of 500 mi/h (db/dt):
Therefore, the rate at which the distance from the plane to the station is increasing is 331 miles per hour.
I hope it helps you!
Step-by-step explanation:
this is only what i got from this question. it may be the only thing we need to do.. or not. but this step is correct for sure
Here,
Selling Price (S.P) = Rs 1869
Loss = 11%
Cost Price (C.P) = ?
Let, C.P be x
Now,
Sp = Cp - loss% of Cp
1869 = x - 11/100*x
1869 = (100x - 11x)/100
186900 = 89x
◆ x = Rs 2100
Cp = Rs 2100
I hope you understand...
It's a Right answer...
Thanks♥♥
13 - ? = 5
13 - 8 = 5! Subtract!