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Aleonysh [2.5K]
3 years ago
6

Can someone help me plzzz

Mathematics
2 answers:
ryzh [129]3 years ago
6 0

Answer:19

Step-by-step explanation:

first write out the equation

3x-27=30

add 27 to both side of the equation

3x=57

the divide 57 by 3

and you get 19

so x=19




Luba_88 [7]3 years ago
3 0
Angle 1 = angle 2 (because vertically opposite angles)


therefore, angle 1=angle 2

3x-27=30

3x=30+27

3x=57

x=57/3

x=19
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Use the zero product property to find the solutions to the equation x^2-13x+30=0
Softa [21]

Answer:

D)  x = 3 , x= 10.

Step-by-step explanation:

Given  : x²-13x+30=0

To find : Use the zero product property to find the solutions to the equation.

Solution : We have given

x²-13x+30=0

On factoring

x²-10x -3x +30=0

On taking x common from first two terms and -3 from last two terms .

x ( x - 10 ) - 3( x - 10 ) = 0

On grouping

(x -3) ( x -10) = 0.

By the zero product property

x -3 = 0

x = 3 ,  

For x - 10 = 0.

x = 10.

Therefore,D)  x = 3 , x= 10.

3 0
3 years ago
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Use ABC shown to the right to answer the following question<br> if BK=21 what is KO
Akimi4 [234]

BK = 2KQ\Leftrightarrow KQ =  \frac{BK}{2}  =  \frac{21}{2}  = 10.5

3 0
4 years ago
What are y'all asking for for chritstmas
Elenna [48]
Answer: I asked for a PS5
3 0
3 years ago
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What is the median of this data set? 20, 34, 38, 100
lubasha [3.4K]
The median is 36.. because you need to find the average of the two middle numbers.
5 0
3 years ago
Plz help
Aleonysh [2.5K]
 1)Rewrite the table:
70,  49,  34.3,  24.01,  11.807

2) write the quotient of each number by the number before & notice the value:

49/70= 0.7
34.3/49 = 0.7
24.01/34.3 =0.7
16.0807/24.01 = 0.67 ≈0.7
You notice this is a geometric progression with r 0.7
The last term in a GP =ar^(n-1)
a=70; r= 0.7 n-1= number of terms (days -1)
For last term = 1 ==> then 1=70(0.7)^(n-1)
1/70 = (0.7)^(n-1)
log(1/70) =log[(0.7)^(n-1) ==> log1 - log 70 = (n-1) log(0.7) & you will find that it need 11.92 days to equal on & to be less than it will necessitate 12 Days

8 0
4 years ago
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