The sine ratio that was applied in step 2 is incorrect, therefore, the first error is in: B. step 2.
<h3>How to Apply the Sine Ratio?</h3>
The sine ratio that is applied when we want to solve a right triangle is, sin ∅ = opposite length / hypotenuse length.
In step 2, the sine ratio applied is wrong because:
- ∅ = W
- Opposite length = XZ
- Hypotenuse length = y
Thus, we should have:
sin(W) = XZ/y
The first error is in: B. step 2.
Learn more about the sine ratio on:
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