Find the greatest common factor (gcf) in each grade between the girls and boys
in 6th grade the gcf is 8
64/8=8 72/8=9
the largest number of groups that can be made equally would be 8 groups of 8 girls and 8 boys
Hope this helps!!
Answer:
Step-by-step explanation:
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<h3>
Answer: Choice A</h3>
Domain = (a,b]
Range = [mc + n,md + n)
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Explanation:
The domain stays the same because we still have to go through f(x) as our first hurdle in order to get g(x).
Think of it like having 2 doors. The first door is f(x) and the second is g(x). The fact g(x) is dependent on f(x) means that whatever input restrictions are on f, also apply on g as well. So going back to the "2 doors" example, we could have a problem like trying to move a piece of furniture through them and we'd have to be concerned about the f(x) door.
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The range will be different however. The smallest value in the range of f(x) is y = c as it is the left endpoint. So the smallest f(x) can be is c. This means the smallest g(x) can be is...
g(x) = m*f(x) + n
g(x) = m*c + n
All we're doing is replacing f with c.
So that means mc+n is the starting point of the range for g(x).
The ending point of the range is md+n for similar reasons. Instead of 'c', we're dealing with 'd' this time. The curved parenthesis says we don't actually include this value in the range. A square bracket means include that value.
Answer:
The transaction will be recorded by the company as :
DR : Non-collectibles $5670
CR : Accounts receivable $5670
Step-by-step explanation:
Amount of money estimated = $5670
The amount which is non-collectible is recorded as a DEBIT transaction by the company because the amount in the non-collectible account can't be received by the company.
But, the amount in the receivables is the amount which is available for receiving and can be received by the company. So, receivable transaction is marked as CREDIT by the company.
Thus, the transaction will be recorded by the company as :
DR : Non-collectibles $5670
CR : Accounts receivable $5670
<h2>
Explanation:</h2><h2>
</h2>
Hello! Remember you have to write complete questions in order to get good and exact answers. Here you forgot to write the relation so I could help you providing my own relation.
Remember that for any relation, we have a set 
that matches the the domain (also called the set of inputs) of the function and the set 
that contains the range (also called the set of outputs).
Suppose our relation is:
So the x-values represents the set A and the y-values the set B. Therefore, by evaluating the x-values into our relation we get:
So in this context, the correct option is:
B) (-9,-8, -7, -6, -5}
