1 year ago

NEED ASAP PLS HELP

Mathematics

1 answer:

Nastasia [14]1 year ago

5 0

The sine ratio that was applied in step 2 is incorrect, therefore, the first error is in: B. step 2.

<h3>How to Apply the Sine Ratio?</h3>

The sine ratio that is applied when we want to solve a right triangle is, sin ∅ = opposite length / hypotenuse length.

In step 2, the sine ratio applied is wrong because:

∅ = W
Opposite length = XZ
Hypotenuse length = y

Thus, we should have:

sin(W) = XZ/y

The first error is in: B. step 2.

Learn more about the sine ratio on:

brainly.com/question/2920412

#SPJ1

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