GIven that $A = (-2, 2)$ and $M = (1, 0)$ , and that point M is the midpoint of AB, the midpoint can be determined as a vectorial sum of A and B. That is:

$M = \frac{1}{2}\cdot A + \frac{1}{2}\cdot B$

The location of B is now determined after algebraic handling:

$\frac{1}{2}\cdot B = M - \frac{1}{2}\cdot A$

$B = 2\cdot M -A$

Then:

$B = 2\cdot (1,0)-(-2,2)$

$B = (2\cdot 1, 2\cdot 0)-(-2,2)$

$B = (2,0) -(-2,2)$

$B = (4,-2)$

Which corresponds to option B.

5 0

2 years ago

True or False? If false provide an example For all integers n, n3 is positive.

Maksim231197 [3]

Answer:

False

Step-by-step explanation:

Explanation is given below.

7 0

2 years ago

F(x) = 5x^3+ 2x^2 - 90x - 36. finding all zeros by factoring and explaining the steps

ella [17]

Answer:

f(x)=5x^3-2x^2-90x-36=0

=x^2(5x-2)-18(5x-2)=(x^2-18)(5x-2)=0

x^2-18=0/5x-2=0

x^2=18=x=9√2

5x-2=0

x=2/5

zeros are 9√2,2/5

8 0

2 years ago