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Olenka [21]
2 years ago
7

Maxine earns $1250 dollars a month. whats is the maximum amount she should use for budget for housing?

Mathematics
1 answer:
jok3333 [9.3K]2 years ago
3 0

Answer:

The National Housing Act of 1937 established guidelines for maximum rents for low-income families.  Originally the maximum rent threshold was set at 20%, however this increased to 30% in 1981 (and has remained at this level ever since).  This figure is used to determine how much of your gross monthly income you should spend on rent.

The 28% Rule is used for determining how much of your gross monthly income should be used for a mortgage, however the FHA's threshold is a little higher at 31% of your gross monthly income on a mortgage.

Renting:

30% of $1,250 = 0.3 × 1250 = $375

Mortgage 28% Rule:

28% of $1,250 = 0.28 × 1250 = $350

Mortgage 31% FHA:

31% of $1,250 = 0.31 × 1250 = $387.50

Therefore, discounting the higher FHA's threshold, the maximum amount to budget for housing is:

  • $375 (if renting)
  • $350 (if buying)
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Step-by-step explanation:

7200 ÷ 300 = 24

30 - 24 = 6

6/24 × 100/1 = 25%

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The top half is called the numerator.
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We have two samples, A and B, so we need to construct a 2 Samp T Int using this formula:

  • \displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}  }  

In order to use t*, we need to check conditions for using a t-distribution first.

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  • Independence for both samples: 130 < all items sold at Location A; 180 < all items sold at Location B -- we can reasonably assume this is true
  • Normality: CLT is not met; <u>n < 30</u> for both locations A and B ∴ <u><em>proceed with caution</em></u>!

<u>Since 2/3 conditions aren't met, we can still proceed with the problem but keep in mind that the results will not be as accurate until more data is collected or more information is given in the problem.</u>

<u>Solve for t*:</u>

<u></u>

We need the <u>tail area </u>first.

  • \displaystyle \frac{1-.9}{2}= .05

Next we need the <u>degree of freedom</u>.

The degree of freedom can be found by subtracting the degree of freedom for A and B.

The general formula is df = n - 1.

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Use a calculator or a t-table to find the corresponding <u>t-score for df = 5 and tail area = .05</u>.

  • t* = -2.015

Now we can use the formula at the very top to construct a confidence interval for two sample means.

  • \overline {x}_A=39
  • s_A=8
  • n_A=13
  • \overline {x}_B = 55
  • s_B=2
  • n_B=18
  • t^{*}=-2.015

Substitute the variables into the formula: \displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}  }.

  • 39-55 \  \pm \ -2.015 \big{(}\sqrt{\frac{(8)^2}{13} +\frac{(2)^2}{18} } } \ \big{)}

Simplify this expression.

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Adding and subtracting 3.73139 to and from -16 gives us a confidence interval of:

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If we want to <u>interpret</u> the confidence interval of (-20.5707, -11.4293), we can say...

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Answer:

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The question specifies that a=42, B=120°, and c=35. Plugging in the values:

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Simplifying gives:

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Answer:

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