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finlep [7]
2 years ago
15

Is (0,0) a solution to this system? y ≤ x^2 + x - 4 y < x^2 + 2x + 1

Mathematics
1 answer:
yaroslaw [1]2 years ago
5 0

( 0,0 ) is not the solution of the first inequality y≤x² +x-4 but ( 0,0) is the solution for the second inequality y <x²+2x+1.

<h3>What is inequality?</h3>

The relation between two expressions that are not equal, employing a sign such as ≠ ‘not equal to’, > ‘greater than, or < ‘less than’

Finding the solution for the inequality is as follows:-

y ≤  x² +x-4 by putting x and y equal to 0.

0 ≤ 0 + 0 -4

0 ≤ - 4

This is incorrect so (0,0) can not be the solution for this inequality.

y < x²+2x+1.

0 < 0 + 0 + 1

0 < 1

This inequality is showing the solution for (0,0)

Therefore ( 0,0 ) is not the solution of the first inequality y≤x² +x-4 but ( 0,0) is the solution for the second inequality y <x²+2x+1.

To know more about inequality follow

brainly.com/question/24372553

#SPJ1

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