Answer:
Anode (oxidation): Cr(s) ⇒ Cr³⁺(aq) + 3 e⁻
Cathode (reduction): Ag⁺(aq) + 1 e⁻ ⇒ Ag(s)
Explanation:
Let's consider the notation of a galvanic cell.
Cr(s) | Cr³⁺(aq) || Ag⁺(aq) | Ag(s)
On the left, it is represented the anode (oxidation) and on the right, it is represented the cathode (reduction).
The half-reactions are:
Anode (oxidation): Cr(s) ⇒ Cr³⁺(aq) + 3 e⁻
Cathode (reduction): Ag⁺(aq) + 1 e⁻ ⇒ Ag(s)
To have the global reaction, we have to multiply the reduction by 3 (so the number of electrons gained and lost are the same) and add both half-reactions.
Global reaction: Cr(s) + 3 Ag⁺(aq) ⇒ Cr³⁺(aq) + 3 Ag(s)
Answer:
1429.32 mmHg
Explanation:
Initial Pressure P1 = 3000.0mmHg
Initial Temperature T1 = 500.0°C + 273 = 573 K ( Converting to kelvin temperature)
Final Temperature T2 = 0.00°C + 273 = 273 K ( Converting to kelvin temperature)
Final Pressure P2 = ?
The pressure of a given amount of gas is directly proportional to the absolute temperature provided volume remains constant.
This is given by the mathematical expression;
P1 / T1 = P2 / T2
Inserting the values;
3000 / 573 = P2 / 273
P2 = 273 * 3000 / 573
P2 = 1429.32 mmHg
It will float, because it is almost weighs like a pen.
Answer:
C: The mobile phase can dissolve the ink and move it up the plate.
Answer:
A
Explanation:
It's A since a theory is a widely accepted explanation of something in the natural world which can be tested but not 100% proven.