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kicyunya [14]
3 years ago
14

What is the value of the equilibrium constant K ?

Chemistry
1 answer:
lorasvet [3.4K]3 years ago
4 0

Answer:

K = 0.0209

Explanation:

K = \frac{[H_{2}][I_{2}]}{[2HI]^{2}}

K = \frac{[4.35 x 10^{-2} ][2.79 x 10^{-2} ]}{[0.241]^{2} }

K = 0.0208958

K = 0.0209

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