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2 years ago

Write the condensed ground-state electron configurations of these transition metal ions, and state which are paramagnetic:

Chemistry

1 answer:

Zinaida [17]2 years ago

7 0

The electron configuration of V³⁺ is [Ar] $3d^2$ . The ion is paramagnetic because it has two unpaired electrons

<h3>What is paramagnetic?</h3>

A weak magnetic field supplied externally can weakly attract some materials, which then create internal magnetic fields that are directed in the same direction as the applied magnetic field. This phenomenon is known as paramagnetic.
Diamagnetic materials, in contrast, are attracted to magnetic fields and produce induced magnetic fields that are directed in the opposite direction from the applied magnetic field.
The majority of chemical elements and some compounds are considered to be paramagnetic materials.
Paramagnetic materials have a relative magnetic permeability that is somewhat more than 1, which makes them attracted to magnetic fields.
The applied field induces a linearly decreasing magnetic moment that is relatively weak.
Modern experiments on paramagnetic materials are frequently done with a sensitive analytical balance since it typically requires a sensitive analytical balance to identify the effect.

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Is food coloring dissolving in water a chemical change

zubka84 [21]

Answer: There no chemical change, but there is a physical change.

Reason: When a substance dissolves in water, the substance retains its molecular identity and simply mixes throughout the water

6 0

3 years ago

Read 2 more answers

On average what is the time between collisions of a xenon atom at 300 K and (a) one torr pressure; (b) one bar pressure.

Amanda [17]

Answer:

(a). 132 × 10^-9 s = 132 nanoseconds.

(b)..176.5 pico-seconds.

Explanation:

(a). At one torr, the first thing to do is to find the speed and that can be done by using the formula below;

Speed = [ (8 × R × T)/ Mm × π]^1/2.

Where Mm = molar mass, T = temperature and R = gas constant.

Speed= [ ( 8 × 8.314 × 300)/ 131.293 × π × 10^-3)^1/2. = 220m/s.

The next thing to do now is to calculate for the degree of collision which can be calculated by using the formula below;

Degree of collision = √2 × π × speed × d^2 × pressure/ K × T.

Note that pressure = 1 torr = 133.32 N/m^2 and d = collision diameter.

Degree of collision = √2 × π × 220 × (4.9 × 10^-10)^2 × 133.32/ 1.38 × 10^-23 × 300.

Degree of collision = 7.55 × 10^6 s^-1.

Thus, 1/ 7.55 × 10^6. = 132 × 10^-9 s = 132 nanoseconds.

(b). At one bar;

1/10^5 × 10^3 × 56.65 = 1.765 × 10^-10 = 176.5 pico-seconds.

6 0

3 years ago

How many grams are in 4.63 x 1024 molecules of CCl4?

MrRa [10]

Answer:

$m=1,182.8g$

Explanation:

Hello!

In this case, since the relationship between molecules and mass is first analyzed via the Avogadro's number to compute the moles in the given molecules:

$mol=4.63x10^{24}molec*\frac{1mol}{6.022x10^{23}molec}=7.69mol$

We now use the molar mass of carbon tetrachloride (153.81 g/mol) to obtain the required grams:

$m=7.69mol*\frac{153.81g}{1mol} \\\\m=1,182.8g$

Best regards!

6 0

3 years ago

9.Competitive inhibition occurs when a O A. substrate binds to an enzyme in the active site and activates the enzyme B. molecule

alexgriva [62]

Answer:

.Competitive inhibition occurs when a O A. substrate binds to an enzyme in the active site and activates the enzyme B. molecule binds to an enzyme in the active site and prevents the substrate from binding C. molecule binds to an enzyme at a site other than the active site and inhibits the substrate from binding O D. molecule binds to an enzyme but doesn't change the shape of the active site Mark for review (Will be highlighted on the review page) << Previous Question Next Question >>

5 0

3 years ago

Calculate ΔHrxn for the following reaction: C(s) + H2O(g) --> CO(g) + H2(g) Use the following reactions and given ΔH values:

valentina_108 [34]

Answer:

ΔH = 130.5 kJ

Explanation:

Hello,

In this case, by using the Hess law, we compute the enthalpy of the required reaction:

C(s) + H2O(g) --> CO(g) + H2(g)

Thus, the first step is to keep the following reaction unchanged:

C (s) + O2 (g) → CO2 (g), ΔH = -393.5 kJ

Next, we invert and halve this reaction:

2 CO (g) + O2 (g) → 2 CO2 (g), ΔH= -566.0 kJ

So the enthalpy of reaction is inverted and halved:

CO2 (g) → CO (g) + 1/2 O2 (g) ΔH= 283 kJ

Then, we also invert and halve this reaction:

2 H2 (g) + O2 (g) → 2 H2O ΔH= -483.6 kJ

So the enthalpy of reaction is inverted and halved as well:

H2O → H2 (g) + 1/2 O2 (g) ΔH= 241.8 kJ

Finally, we add the three reactions to obtain the required reaction:

= C (s) + O2 (g) + CO2 (g) + H2O → H2 (g) + 1/2 O2 (g) + CO (g) + 1/2 O2 (g) + CO2 (g)

= C (s) + O2 (g) + CO2 (g) + H2O → H2 (g) + O2 (g) + CO (g) + CO2 (g)

= C (s) + H2O → H2 (g) CO (g)

So enthalpy is computed by:

ΔH = -393.5 kJ + 283 kJ + 241.8 kJ

ΔH = 130.5 kJ

Best regards.

5 0

3 years ago