Answer:
900<x<1100
Step-by-step explanation:
The third side must be greater than the difference of the other two sides
10000- 1000 < 10x
9000< 10x
Divide by 10
9000/10 < x
900 < x
The third side must be smaller than the sum of the other two sides
10000+1000 > 10x
11000>10x
Divide by 10
11000/10>10x/10
1100>x
900<x<1100
The real solutions the equation as given in the task content; x² = 225 are; +25 and -25.
<h3>What are the real solutions of the equation as given in the task content?</h3>
It follows from the task content that the real solutions of the equation as given in the task content can be determined as follows;
x² = 225
x = ± 15
Therefore, the real solutions of the equation are; +25 and -25.
Read more on real solutions of equations;
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The general equation for a circle is:
Where the center is (h,k) and the radius is r.
The equation we are given is:
From this, the center is (2,-3), and the radius is 
, or 
.
Let me know if you have any questions, thanks!
Solve by substitution : Solve for x or y in one equation and substitute it into the other equation in place of the variable that corresponds to it .
