9514 1404 393
Answer:
2.20×10^10 km³
Step-by-step explanation:
The formulas for area (A) and volume (V) of a sphere are ...
A = 4πr²
V = 4/3πr³ = (r/3)A
The radius can be found from the area as ...
r = √(A/(4π)) = (1/2)√(A/π)
Then the volume in terms of the area is ...
V = (1/3)(1/2)√(A/π) · A = A^(3/2)/(6√π)
Filling in the given value of area, we find the volume to be ...
V = (3.7959×10^7)^(3/2)/(6√π) ≈ 2.1991×10^10 . . . . km³
Rounded to 3 significant figures, the volume of the moon is about ...
V ≈ 2.20×10^10 km³
Answer:
pa brainiest muna alam ko yan
For this case we have the following polynomial:
![x ^ 2 - 25 = 0](https://tex.z-dn.net/?f=%20x%20%5E%202%20-%2025%20%3D%200%20%20)
We can solve the polynomial by factoring.
We have then:
![(x + 5) (x-5) = 0](https://tex.z-dn.net/?f=%20%28x%20%2B%205%29%20%28x-5%29%20%3D%200%20%20)
From here, we clear the solutions of the equation.
Solution 1:
![x + 5 = 0\\x = -5](https://tex.z-dn.net/?f=%20x%20%2B%205%20%3D%200%5C%5Cx%20%3D%20-5%20)
Solution 2:
![x-5 = 0\\x = 5](https://tex.z-dn.net/?f=%20x-5%20%3D%200%5C%5Cx%20%3D%205%20)
Answer:
the solutions to the quadratic equation x ^ 2 - 25 = 0 are:
x = 5 and x = -5
Answer:
Rs 104z
Step-by-step explanation:
litres cost Rs 4z
1litre cost Rs 4z×4 =16z
⇒
⇒6.5 litres cost Rs 16z×6.5 =Rs 104z
Answer:
b) 2.00
Step-by-step explanation:
For each name, there are only two possible outcomes. Either it is authentic, or it is not. The probability of a name being authentic is independent of any other name. This means that we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
![E(X) = np](https://tex.z-dn.net/?f=E%28X%29%20%3D%20np)
She randomly selects five names from the list for validation.
This means that ![n = 5](https://tex.z-dn.net/?f=n%20%3D%205)
40% of the names on the list are non-authentic
This means that ![p = 0.4](https://tex.z-dn.net/?f=p%20%3D%200.4)
The expected (average) value of x is
![E(X) = np = 5*0.4 = 2](https://tex.z-dn.net/?f=E%28X%29%20%3D%20np%20%3D%205%2A0.4%20%3D%202)
The correct answer is given by option B.