The enthalpy change, ΔH for the following reaction
2NH₃ + 5/2O₂ --> 2NO (g) + 3 H₂O (g) is -452.76 kJ.
<h3>What is enthalpy change, ΔH, of a reaction?</h3>
The enthalpy change of a reaction is the heat changes that occurs when a reaction proceeds to formation of products.
Formula for the enthalpy change;
ΔH = ΔH of products - ΔH of reactants
The equation of the reaction is given below
2NH₃ + 5/2O₂ --> 2NO (g) + 3 H₂O (g)
for the above reaction ;
- ΔH of NO = 90.25 KJ
- ΔH of H₂O = - 241.82 KJ
- ΔH of NH₃ = - 46.1 KJ
- ΔH of O₂ = 0 KJ
Thus,
ΔH of Reaction = (90.25 x 2) + (-241.82 x 3) + (-46.1 x 2) = - 452.76 kJ
Therefore, the enthalpy change, ΔH for the following reaction
2NH₃ + 5/2O₂ --> 2NO (g) + 3 H₂O (g) is - 452.76 kJ.
Learn more about enthalpy change here :
brainly.com/question/14047927
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