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Nonamiya [84]
2 years ago
10

Determine the ΔH for the following reaction 2NH3 + 5/2O2 = 2NO(g) + 3 H2O(g)

Chemistry
2 answers:
beks73 [17]2 years ago
4 0

The enthalpy change, ΔH for the following reaction 2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g) is -452.76 kJ.

<h3>What is enthalpy change, ΔH, of a reaction?</h3>

The enthalpy change of a reaction is the heat changes that occurs when a reaction proceeds to formation of products.

  • Enthalpy change, ΔH = ΔH of products - ΔH of reactants

The equation of the reaction is given below

2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g)

\Delta{H_{f}\:of\:NO = 90.25 kJ; \Delta{H_{f}\:of\:H_{2}O =-241.82kJ;  \Delta{H_{f}\:of\:NH_{3} =-46.1 kJ;  \Delta{H_{f}\:of\:O_{2} =0

\Delta{H_{f}\:of\:rxn = (90.25*2)+(-241.82*3)-( -46.1*2)= -452.76\:kJ

Therefore, the enthalpy change, ΔH for the following reaction 2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g) is -452.76 kJ.

Learn more about enthalpy change at: brainly.com/question/14047927

#SPJ1

Grace [21]2 years ago
3 0

The enthalpy change, ΔH for the following reaction

2NH₃ + 5/2O₂ --> 2NO (g) + 3 H₂O (g)  is -452.76 kJ.

<h3>What is enthalpy change, ΔH, of a reaction?</h3>

The enthalpy change of a reaction is the heat changes that occurs when a reaction proceeds to formation of products.

Formula for the enthalpy change;

ΔH = ΔH of products - ΔH of reactants

The equation of the reaction is given below

2NH₃ + 5/2O₂ --> 2NO (g) + 3 H₂O (g)

for the above reaction ;

  • ΔH of NO  =  90.25 KJ
  • ΔH of H₂O = - 241.82 KJ
  • ΔH of NH₃ = - 46.1 KJ
  • ΔH of O₂ = 0 KJ

Thus,

ΔH of Reaction = (90.25 x 2) + (-241.82 x 3) + (-46.1 x 2) = - 452.76 kJ

Therefore, the enthalpy change, ΔH for the following reaction

2NH₃ + 5/2O₂ --> 2NO (g) + 3 H₂O (g)  is - 452.76 kJ.

Learn more about enthalpy change here :

brainly.com/question/14047927

#SPJ1

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The reaction between nitrogen and oxygen is given below: 2 N2(g) + O2(g) 2 N2O(g) We therefore know that which of the following
Ostrovityanka [42]

Answer:

  • a)  2N₂O(g) → 2N₂(g)  + O₂(g)

Explanation:

Arrange the equations in the proper way for better understanding.

T<em>he reaction between nitrogen and oxygen is given below:</em>

<em />

  • <em>2N₂(g) + O₂(g) → 2N₂O(g)</em>

<em />

<em>We therefore know that which of the following reactions can also occur?</em>

<em />

  • <em>a)  2N₂O(g) → 2N₂(g)  + O₂(g)</em>
  • <em>b)  N₂(g) + 2O₂(g) → 2NO₂(g)</em>
  • <em>c)  2NO₂(g) → N₂(g) + 2O₂(g)</em>
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<h2>Solution</h2>

Notice that the first equation,  a) 2N₂O(g) → 2N₂(g)  + O₂(g), is the reverse of the original equation, 2N₂(g) + O₂(g) → 2N₂O(g).

The reactions in gaseous phase are reversible reactions that can be driven to one or other direction by modifying the conditions of temperature or pressure.

Thus, the equilibrium equation would be:

  • 2N₂(g) + O₂(g) ⇄ 2N₂O(g)

Which shows that both the forward and the reverse reactions occur.

Whether one or the other are favored would depend on the temperature and pressure: high temperatures would favor the reaction that consumes more heat (the endothermic reaction) and high pressures would favor the reaction that consumes more moles.

Thus, by knowing that one of the reactions can occur you can conclude that the reverse reaction can also occur.

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