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m_a_m_a [10]
3 years ago
5

The expression below was formed by combining different gas laws. V is proportional to StartFraction n T over P EndFraction. Whic

h law was used to determine the relationship between the volume and the number of moles in this equation?
Chemistry
1 answer:
Ronch [10]3 years ago
3 0

Answer:

The Ideal gas law

Explanation:

From the given question, we have:

V \alpha \frac{nT}{P}

where each variable has its usual meaning.

Thus,

V = \frac{nRT}{P}

where R is the ideal gas constant

cross multiply to have;

PV = nRT

This implies that the volume of the gas is directly proportional to the number of moles of the gas.

Therefore, the law can be used to determine the relationship between the volume and number of moles is the ideal gas law.

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The standard enthalpy change for the following reaction is 873 kJ at 298 K.
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Answer:  - 436.5 kJ.

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation.

The given chemical reaction is,

2KCl(s)\rightarrow 2K(s)+Cl_2(g)  \Delta H_1=873kJ

Now we have to determine the value of \Delta H for the following reaction i.e,

K(s)+\frac{1}{2}Cl_2(g)\rightarrow KCl(s) \Delta H_2=?

According to the Hess’s law, if we divide the reaction by half then the \Delta H will also get halved and on reversing the reaction , the sign of enthlapy changes.

So, the value \Delta H_2 for the reaction will be:

\Delta H_2=\frac{1}{2}\times (-873kJ)

\Delta H_2=-436.5kJ

Hence, the value of \Delta H_2 for the reaction is -436.5 kJ.

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