Question

44. The maximum horizontal distance a boy can throw a ball is 50 m. Assume he can throw with the same initial speed at all angles. How high does he throw the ball when he throws it straight upward

Answer 1

The maximum height reached by the ball thrown by the boy is determined as 12.5 m.

Angle of the projection

The angle of projection of the ball is calculated as follows;

R = u²sin2θ/g

• at maximum range, θ = 45 degrees

50 =  u²/9.8

u² = 50 x 9.8

u² = 490

u = 22.14 m/s

Maximum height of the ball

H = u²sin²θ/2g

H = (22.14² x (sin45)²)/(2 x 9.8)

H = 12.5 m

Thus, the maximum height reached by the ball thrown by the boy is determined as 12.5 m.

Learn more about maximum height here: brainly.com/question/12446886

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