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Flauer [41]
3 years ago
8

This square solenoid has sides length 25 cm, and 100 turns of wire. The resistance is 10 ohms. Find the magnitude of the induced

emf in the coil if the magnetic field of 10 T is passing through the face of the loop as pictured. What is the induced current in the wire. Find the emf and current if the solenoid was a circle with radius 25 cm instead of a square.
Physics
1 answer:
Lynna [10]3 years ago
5 0

Explanation:

Area of square = 25^2 = 625 cm^2 or  = 0.0625 m^2

number of turns = 100

Solenoid resistance = 10 ohms

now we know , Φ = B.A

where , Φ = magnetic flux, B= magnetic field strength, and A = area.

Φ = 10 × 0.0625 = 0.625 W

induced emf ε = dΦ/dt = d(BA)/dt  =0

This is because both B and A are constants.

⇒ Induced current is also zero.

Replacing square by a circle will not change situation as the value of B and A will remain constant with time hence, no emf induced, so no current induced.

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5. What is the velocity of a 0.5 kg ball that has a momentum of 3.00 kg m/s?
kow [346]

Answer:

6 m/s

Explanation:

p=mv

p=3 kg.m/s

m=0.5 kg

rearrange and substitute to find v:

(3)=(0.5)v

v=3/0.5

v=6 m/s

3 0
2 years ago
A nerve signal travels 150 meters per second. Determine the number of kilometers that the nerve signal will travel in the same t
joja [24]

Explanation:

It is given that,

A nerve signal travels 150 meters per second. It is the speed of the nerve signal. We need to convert the number of kilometers that the nerve signal will travel in the same time.

We know that,

1 kilometer = 1000 meter

1 hour = 3600 seconds

150\ \dfrac{m}{s}=150\times \dfrac{1/1000\ km}{1/3600\ h}

150\ m/s=540\ km/h

So, the nerve signal will travel at the rate of 540 km/h. Hence, this is the required solution.

6 0
3 years ago
The graph shows the federal budget from 1980 to 2010. In which period did the federal budget show the greatest deficit?
kodGreya [7K]

Answer:

2000 to 2010

Explanation:

sorry I'm just guessing

8 0
2 years ago
A weightlifter lifts a 250-kg mass 0.5 meters above his head, how much PEg does the mass have (Note: g=9.8 m/s2)? Round your ans
morpeh [17]

Answer:

1225 J

Explanation:

The Gravitational potential energy (PEG) gained by a mass lifted above the ground is given by

PE=mgh

where

m is the mass

g = 9.8 m/s^2 is the acceleration due to gravity

h is the height at which the object has been lifted

In this problem, we have

m = 250 kg

h = 0.5 m

So, the PE of the object is

PE=(250 kg)(9.8 m/s^2)(0.5 m)=1225 J

6 0
3 years ago
Read 2 more answers
a bal is launched upward with a velocity of v0 from the edge of a cliff of height D. it reaches a maximum height of H above its
lilavasa [31]

Answer:

D/H =15

Explanation:

  • We can find first the peak height H, taking into consideration, that at the maximum height, the ball will reach momentarily to a stop.
  • At this point, we can find the value of H, applying the following kinematic equation:

       v_{f} ^{2} -v_{0} ^{2} = 2* g* H (1)

  • If vf=0, if we assume that the positive direction is upwards, we can find the value of H as follows:

       H = \frac{v_{0} ^{2} }{2*g} (2)

  • We can use the same equation, to find the value of D, as follows:

        v_{f} ^{2} -v_{1} ^{2} = 2* g* D (3)

  • In order to find v₁, we can use the same kinematic equation that we used to get H, but now, we know that v₀ = 0.
  • When we replace these values in (1), we find that  v₁ = -v₀.
  • Replacing in (3), we have:

        (4*v_{0})^{2} - (-v_{0}) ^{2}  = 2* g* D\\ \\ 15*v_{0}^{2}  = 2*g*D

  • Solving for  D:

       D = \frac{15*v_{0} ^{2} }{2*g}

  • From (2) we know that H can be expressed as follows:

       H = \frac{v_{0} ^{2} }{2*g}

  • ⇒ D = 15 * H

        \frac{D}{H} = 15

3 0
3 years ago
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