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3 years ago

The temperature of a liquid is 75°F. What is its temperature in °C?

2 answers:

7 0

The answer is C. 24°C.

We have formula: °C = (°F – 32) x 5/9
°C = ?
If we know that the temperature of the liquid is 75°F, let's just substitute it in the formula:
°C = (75 – 32) x 5/9
°C = 43 x 5/9
°C = 23.89
°C ≈ 24

Ierofanga [76]3 years ago

5 0

The correctvanswer is D

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Which of the following shows the prefixes in order from largest to smallest? centi, deci, nano

Burka [1]

Deci, Centi, then Nano is the correct order from largest to smallest

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4 years ago

A student wants to use a ramp to move boxes into a truck bed that is 3 m high. He has a choice of 2 different ramps. The length

pishuonlain [190]

Answer:

the ramp with 6 m length will be easier to work with.

Explanation:

the mechanical advantage of the ramp can be calculated to find out which ramp will be easier to work with. The ramp with greater mechanical advantage will be easier to work with. The formula for the mechanical advantage of ramp is given as follows:

$M.A = \frac{L}{h} \\\\$

where,

M.A = Mechanical Advantage = ?

L = Length of Ramp

h = height of ramp = 3 m

FOR L =4 m:

$M.A = \frac{4\ m}{3\ m}\\\\M.A = 1.33$

FOR L = 6 m:

$M.A = \frac{6\ m}{3\ m}\\\\M.A = 2$

Since, the ramp with length 6 m has a greater mechanical advantage.

Therefore, the ramp with 6 m length will be easier to work with.

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3 years ago

A 111 kg linebacker running at 1.9 m/s and a 82 kg quarterback running at 3 m/s have a head-on collision in midair. The lineback

EleoNora [17]

Answer:

Explanation:

mass of linebacker, m = 111 kg

initial velocity, u = 1.9 m/s

mass of quarterback, m' = 82 kg

initial velocity, u' = 3 m/s

(a) Let they are moving in the same direction, the velocity is v after collision.

Use conservation of momentum

m u + m' u' = (m + m') v

111 x 1.9 + 82 x 3 = (111 + 82) v

v = 2.4 m/s

Let they are moving in opposite direction, the velocity is v after collision.

Use conservation of momentum

m u - m' u' = (m + m') v

111 x 1.9 - 82 x 3 = (111 + 82) v

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3 years ago

Mechanical waves are classified according to

eimsori [14]

Answer:

Mechanical waves are classified by how they move.

Explanation:

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3 years ago

Transverse waves are sent along a 4.50 m long string with a speed of 85.00 m/s. The string is under a tension of 20.00 N. What i

frutty [35]

Answer:

m = 0.0125 kg

Explanation:

Let us apply the formula for the speed of a wave on a string that is under tension:

$v = \sqrt{\frac{F}{\mu} }$

where F = tension force

μ = mass per unit length

Mass per unit length is given as:

μ = m / l

where m = mass of the string

l = length of the string

This implies that:

$v = \sqrt{\frac{F}{m/l} }\\ \\v = \sqrt{\frac{F * l}{m} }$

Let us make mass, m, the subject of the formula:

$v^2 = \frac{F * l}{m}\\\\m = \frac{F * l}{v^2}$

From the question:

F = 20 N

l = 4.50 m

v = 85 m/s

Therefore:

$m = \frac{20 * 4.5}{85^2}\\\\m = \frac{90}{7225}\\ \\m = 0.0125 kg$

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3 years ago