Question

a car initially traveling at 5 m/s accelerates for 2 seconds at 3 m/s. how far does it travel during this time?

Answer 1

Answer:

x = 16 [m]

Explanation:

This problem can be solved using the following equation of kinematics.

$v_{f}=v_{o}+a*t$

where:

Vf = final velocity [m/s]

Vo = initial velocity = 5 [m/s]

a = acceleration = 3 [m/s²]

t = time = 2 [s]

$v_{f}=5+3*(2)\\v_{f}=11[m/s]$

Now we can find the displacement using the following equation of kinematics.

$v_{f}^{2} =v_{o}^{2} +2*a*x\\11^{2}=5^{2} +2*3*x\\96=6*x\\x=16[m]$