It is 6 because 1000 would not be the appropiate answer
Answer:
31.9secs
6,183.3m
Step-by-step explanation:
Given the equation that models the height expressed as;
h(t ) = -4.9t²+313t+269
At the the max g=height, the velocity is zero
dh/dt = 0
dh/dt = -9,8t+313
0 = -9.8t + 313
9.8t = 313
t = 313/9.8
t = 31.94secs
Hence it takes the rocket 31.9secs to reach the max height
Get the max height
Recall that h(t ) = -4.9t²+313t+269
h(31.9) = -4.9(31.9)²+313(31.9)+269
h(31.9) = -4,070.44+9,984.7+269
h(31.9) = 6,183.3m
Hence the maximum height reached is 6,183.3m
Answer:
8
Step-by-step explanation:
x=average
(x+x+x+x)/4=average
to increase x by 2 you add 2
x+2=average
(x+2+x+2+x+2+x+2)=4=(4x+8)/4=x+2
you'd have to increase the sum by 8 to make the numbers' averages' go up by 2
Answer:
Step-by-step explanation:
y=-1/2(x+10)^2+14
2y=-(x+10)^2+28
(x+10)^2=28-2y
L.H.S. is positive.
so 28-2y≥0
28≥2y
or 2y≤28
or y≤ 14
Range is (-∞,14]
