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2 years ago

Which represents the inverse of the

Mathematics

1 answer:

Mekhanik [1.2K]2 years ago

8 0

Answer:

Step-by-step explanation:

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20% of 145<br> Please show work!!!!<br> I need an answer ASAP!!!!

IRISSAK [1]

Answer:

20/100 × 145

2/10 × 145

290 ÷ 10 = 29

Thus, 20% of 145 is 29

5 0

2 years ago

Read 2 more answers

Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$

NOTE: sin²θ + cos²θ = 1

$\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}$

$\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}$

$\dfrac{2sec^2\theta}{tan^2\theta-1}$

Left side = Right side <em>so proof is complete</em>

8 0

3 years ago

Read 2 more answers

Pleae help me i will mark you brainliestttttttttt

muminat

Answer:

The last one.

Step-by-step explanation:

7 0

2 years ago

Eight friends share 2 pumpkin pies equally. What fraction of a pumpkin pie does each friend get?

Pachacha [2.7K]

Answer:

1/4 of a pie

Step-by-step explanation:

2 / 8 = 1/4

6 0

3 years ago

How do u write 5(2x - 1) in a distributive property

Nookie1986 [14]

Answer:

5(2x-1) = 5(2x) - 5(1)

Step-by-step explanation:

The distributive property states that multiplying a sum or difference of two terms by a number is equal to multiplying the same number with each term of the sum or difference separately and then adding the products.

It can be written as:

a(b+c) = ab + ac

a(b-c) = ab - ac

So, for the given question,

=>5(2x-1) = 5(2x) - 5(1)

5 0

3 years ago