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Orlov [11]
3 years ago
8

How to find function of x

Mathematics
1 answer:
AfilCa [17]3 years ago
3 0

Answer:

By using function notation

This question os incomplete

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Jade says that the absolute value of a number and the opposite of a number is the same thing. Is Jade correct? Use examples to h
avanturin [10]

Answer:

No, the absolute value of a number is different from the opposite.

Step-by-step explanation:

For example, the absolute value of 4 is 4.

l4l = 4

But the opposite of 4 is -4.

Absolute value is ALWAYS positive, but the opposite of a positive number is a negative number.

8 0
3 years ago
Usama needs to read 6 novels each month.
Delicious77 [7]

Answer:

78 novels

Step-by-step explanation:

N= novels

M= month

6N = 1M

? = 13M

6N × 13M= 78NM

78NM ÷ 1M

cancel M, therefore;

the number of novels Usama needs to read in 13 months is 78.

5 0
2 years ago
Read 2 more answers
The line integral of (2x+9z) ds where the curve is given by the parametric equations x=t, y=t^2, z=t^3 for t between 0 and 1. Pl
Naya [18.7K]
Let r = (t,t^2,t^3)

Then r' = (1, 2t, 3t^2)

General Line integral is:
\int_a^b f(r) |r'| dt

The limits are 0 to 1
f(r) = 2x + 9z = 2t +9t^3
|r'| is magnitude of derivative vector \sqrt{(x')^2 + (y')^2 + (z')^2}

\int_0^1 (2t+9t^3) \sqrt{1+4t^2 +9t^4} dt

Fortunately, this simplifies nicely with a 'u' substitution.

Let u = 1+4t^2 +9t^4

du = 8t + 36t^3  dt

\int_0^1 \frac{2t+9t^3}{8t+36t^3} \sqrt{u}  du \\  \\ \int_0^1 \frac{2t+9t^3}{4(2t+9t^3)} \sqrt{u}  du \\  \\  \frac{1}{4} \int_0^1 \sqrt{u}  du

After integrating using power rule, replace 'u' with function for 't' and evaluate limits:
=\frac{1}{4} |_0^1 (\frac{2}{3}) (1+4t^2 +9t^4)^{3/2} \\  \\ =\frac{1}{6} (14^{3/2} - 1)
7 0
3 years ago
Twelve percent of U.S. residents are in their forties. Consider a group of nine U.S. residents selected at random. Find the prob
miskamm [114]

Answer:

The probability is 28 % ( approx )

Step-by-step explanation:

Since, there are only two possible outcomes in every trails ( residents are in their forties or not ),

So, this is a binomial distribution,

Binomial distribution formula,

Probability of success in x trials,

P(x)=^nC_x p^x q^{n-x}

Where, ^nC_x=\frac{n!}{x!(n-x)!}

p and q are probability of success and failure respectively and n is the total number of trials.

Let X be the event of resident who are in his or her forties.

Here, p = 12% = 0.12,

⇒ q = 1 - p = 1 - 0.12 = 0.88,

n = 9,

Hence, the probability that two or three of the people in the group are in their forties = P(X=2) + P(X=3)

^9C_2 (0.12)^2 (0.88)^{9-2}+^9C_3 (0.12)^3 (0.88)^{9-3}

=36(0.12)^2 (0.88)^7+84(0.12)^3 (0.88)^6

=0.279266611163

\approx 0.28

=28\%

7 0
3 years ago
Help plsssss I will mark as brainlest if correct
Gennadij [26K]

Replace x with a couple of numbers, solve for Y them mark those points on the graph and connect with a line.

See picture:

5 0
3 years ago
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