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3 years ago

How to find function of x

Mathematics

1 answer:

AfilCa [17]3 years ago

3 0

Answer:

By using function notation

This question os incomplete

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Identify the reflection of the figure with vertices E(8,4), F(-16,-8), and G(24,-16) across the y-axis.

Dafna1 [17]

Answer:

$\boxed{\text{E$'$(-8, 4), F$'$(16,-8), G$'$(-24,-16)}}$

Step-by-step explanation:

When you reflect a point (x, y) in the y-axis, the y-coordinate remains the same, but the x-coordinate gets the opposite sign. Thus,

E (8,4) ⟶ E' (-8,4)

F (-16,-8) ⟶ F' (16,-8)

G (24,-16) ⟶ G' (-24,-16)

$\text{The reflected figure has coordinates } \boxed{\textbf{E$'$(-8, 4), F$'$(16,-8), G$'$(-24,-16)}}$

The figure EFG and its reflection E'F'G' are shown in the diagram below.

6 0

3 years ago

(1 ÷ x- 1)+(2÷ x+2)=(3÷2) solve and check for extraneous solutions

Sliva [168]

$\frac{1}{x-1}+ \frac{2}{x+2}= \frac{3}{2}$
$\frac{1(x+2)}{(x-1)(x+2)}+ \frac{2(x-1)}{(x+2)(x-1)}= \frac{3(x-1)(x+2)}{2}$
$\frac{x+2+2(x-1)}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}$
$\frac{x+2+2x-1}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}$
$\frac{3x+1}{(x-1)(x+2)}= \frac{3(x^2+x-2)}{2}$
$\frac{}{(x-1)(x+2)}= \frac{3x^2+3x-6)}{2}$
$\frac{3x+1}{(x^2+x-2)}= \frac{3x^2+3x-6)}{2}$
$\frac{2(3x+1)}{2(x^2+x-2)}= \frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}$
$\frac{2(3x+1)}{2(x^2+x-2)}-\frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}=0$
$\frac{2(3x+1)-3x^2+3x-6}{2(x^2+x-2)}=0$

this will be continued

5 0

4 years ago

What’s a median for geometry

LenaWriter [7]

Answer:

In geometry, a median of a triangle is a line segment joining a vertex to the midpoint of the opposite side, thus bisecting that side. Every triangle has exactly three medians, one from each vertex, and they all intersect each other at the triangle's centroid.

3 0

4 years ago

Suppose that several insurance companies conduct a survey. They randomly surveyed 350 drivers and found that 280 claimed to alwa

KATRIN_1 [288]

Answer:

Lower limit = 0.76

Upper limit = 0.84

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 350

Number of drivers that buckle = 280

Formula: