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OleMash [197]
1 year ago
11

The profit from a business is

Mathematics
1 answer:
GuDViN [60]1 year ago
3 0

First of all we will understand the question!!

<em>The</em><em> </em><em>question</em><em> </em><em>is</em><em> </em><em>saying</em><em> </em><em>that</em><em> </em><em>you</em><em> </em><em>are</em><em> </em><em>given</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>and</em><em> </em><em>you</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>x</em><em> </em><em>which</em><em> </em><em>will</em><em> </em><em>give</em><em> </em><em>the</em><em> </em><em>maximum</em><em> </em><em>profit</em><em>.</em><em>.</em><em>.</em><em> </em><em>Lets</em><em> </em><em>solve</em><em> </em><em>it</em><em> </em><em>by</em><em> </em><em>finding</em><em> </em><em>the</em><em> </em><em>extrema</em><em> </em><em>using</em><em> </em><em>the</em><em> </em><em>vertex</em>

<em>\rm \: p(x) =  - 5 {x}^{2}  + 30x + 8</em>

  • <u>Identify the coefficients a and b of the quadratic function</u>

<em>\rm \: p(x) =   { - 5x}^{2}  + 30x + 8  \\  \rm \: a =  - 5 \: and \: b \:  = 30</em>

  • <u>Since a<0, the function has the maximum value at x, calculated by substituting a and b into x=-b/2a</u>

<u>\rm \: x =  \frac{30}{ 2 \times  (- 5)}</u>

  • <u>Solve</u><u> </u><u>the</u><u> </u><u>equation</u><u> </u><u>for</u><u> </u><u>x</u><u> </u>

<u>\rm \: x = 3</u>

  • <u>The maximum of the quadratic function is at </u><u>x</u><u>=</u><u>3</u>
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   Properties of Logs

logb(x/y) = log<span>bx</span> - log<span>by</span>.

therefore

log5 (4/7)= log5 (4)- log5 (7)

<span>Solve log 5 (4) and log 5 (7)  with the base change of the logarithm</span>

<span>log 5 4 = log 4 / log 5 </span>

 Use the calculator: 

<span> <span>log 5 4 =0.8613531161 </span></span>

 log 5 7 = log 7 / log 5 

<span>log 5 7 =1.2090619551</span>

<span>log5 (4/7)= log5 (4)- log5 (7)=-0.347708839</span>

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Answer:

The probability that they will teach different courses is \frac{2}{3}.

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here <em>x</em> represents the course taught by the first part-time instructor and <em>y</em> represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

Compute the probability that they will teach different courses as follows:

P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}

Thus, the probability that they will teach different courses is \frac{2}{3}.

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