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Alex Ar [27]
2 years ago
12

What is the greatest common factor of 20 and 10?

Mathematics
2 answers:
Nana76 [90]2 years ago
7 0
10 is the gcf for 20 and 10
Naddika [18.5K]2 years ago
6 0

Answer:

Step-by-step explanation:

The factors common to 20 and 10 are 1, 5 and 10.  The largest of these is 10.  That's the GCF of 20 and 10.

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If f(x)=3x-2,find f(8)-f(-5)
Alexandra [31]

To find both f(8) and f(-5), we will need to plug in their values for x and solve for each. Then, we can subtract them to find the final answer.

Finding f(8):

f(8) = 3(8) - 2

f(8) = 24 - 2

f(8) = 22

Finding f(-5):

f(-5) = 3(-5) - 2

f(-5) = -15 - 2

f(-5) = -17

Subtracting f(8) and f(-5):

f(8) - f(-5)

22 - - 17

22 + 17

39

Hope this helps!! :)

6 0
3 years ago
What is the graph of y = 2f(x)
Licemer1 [7]

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8 0
3 years ago
How much $ do you make in an hour if you earn $42.25 in 6.5 hours?
mafiozo [28]
$6.50 per hour. 42.25/6.5=6.5
7 0
3 years ago
Owen plots the numbers 4, –6, –8, and –3 on a horizontal number line. Which list shows the numbers in the order in which they wo
Maru [420]

Answer:

-8  -6   -3   4

Step-by-step explanation:

In a number line, the numbers on the are lesser than the numbers on the right. In a number line with integers, numbers going to the right from the midline which is 0 is positive and increases as you move to the right. As you move to the left, the numbers are negative and decreases as you move further to the left.

Attached is a picture of how it would look on a number line.

4 0
4 years ago
Jharana got Rs.1881 interest of certain sum for 2year at 9% compounded yearly.find the sum.​
Lana71 [14]

The principal sum is Rs.10,000

Step-by-step explanation:

The formula of compound interest is:

I=P(1+\frac{r}{n})^{nt}-P where:

  • I is the interest
  • P is the principal investment amount (the initial deposit or loan amount)
  • r is the annual interest rate (decimal)
  • n is the number of times that interest is compounded per unit t
  • t is the time the money is invested or borrowed for

Jharana got Rs.1881 interest of certain sum for 2 year at 9%

compounded yearly

∵ I = Rs.1881

∵ r = (9/100) = 0.09

∵ n = 1 ⇒ compounded yearly

∵ t = 2 years

Substitute all of these values in the rule above

∴ 1881=P(1+\frac{0.09}{1})^{(1)(2)}-P

∴ 1881 = P(1 + 0.09)² - P

∴ 1881 = P(1.09)² - P

∴ 1881 = 1.1881 P - P

∴ 1881 = 0.1881 P

- Divide both sides by 0.1881

∴ P = 10,000

The principal sum is Rs.10,000

Learn more:

You can learn more about the interest in brainly.com/question/11149751

#LearnwithBrainly

3 0
3 years ago
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