Your answer is definitely right good job
First you do 4500 × 0.04
Then take that number and add it to 4500
Answer:
A. 23+(6-1)x-3
B. 93
Step-by-step explanation:
a) Nth term = F + (N - 1) x D, where F=First term, N=Number of terms, D=Common difference
6th row = 23 + (6 - 1) x -3
= 23 + (5) x -3
= 23 + (-15)
= 8 - number of boxes in the top row.
b) Sum = N/2[2F + (N - 1) x D]
= 6/2[2*23 + (6 - 1) x -3]
= 3 [46 + (5) x -3 ]
= 3 [46 + -15 ]
= 3 [ 31 ]
= 93 - total number of boxes in the entire display.
Hope this helps! Its 3:25 AM for me too so I know how you feel.
Answer:
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