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NARA [144]
2 years ago
10

Help

Mathematics
1 answer:
alisha [4.7K]2 years ago
7 0

Answer:

a. x^{2}  + 3y^{3}

b. 3y^{3} -6

c. 5x -3

d. -6t - 5

Step-by-step explanation:

When a number has the same variable as another, you can add or subtract them

So for the first one, you can do

5x^{2} -4x^{2} = 1x^{2}  = x^{2}

(But don't forget the 3y^{3}!)

So it is:

x^{2}  + 3y^{3}

Continue this process for the rest of them

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Irene made a mistake when she solved this inequality:
rosijanka [135]
She made a mistake in steps 3-4
6 0
3 years ago
Resuelve los problemas de una bodega que exporta tomates al extranjero
Dovator [93]

Answer:

1. 34.42 Toneladas

2. 28.640 toneladas

3. 38 toneladas

4.\frac{15}{10} o 1\frac{5}{10}

5.\frac{16}{6} o 2\frac{4}{6}

6.\frac{8}{4} o 2

1.1 Solucioné el problema convirtiendo el .25 en fracción.

2.1 Conviertes el denominador en el mismo buscando el minimo comun multiplo

3.1 0.099

\frac{1}{4}

\frac{1}{3}

\frac{2}{3}

0.7

0.75

1.1

\frac{3}{2}

Step-by-step explanation:

Acuerdate que para solucionar las fracciones mixtas solo tienes que dividir el denominador al nominador, por ejemplo en si tienes \frac{10}{3} entonces el 3 cabe 3 veces en el 10, y sobra 1, entonces quedamos que en mixta la fracción sería 3\frac{1}{3}

Entonces una vez que recordamos eso, podemos resolver los problemas de fracciones sin ningún problema vamos a resolver la número 4:

\frac{8}{10} +\frac{7}{10}

Como el denominador es igual, sólo sumamos el nominador:

\frac{8+7}{10}

\frac{15}{10}

Cómo el 10 cabe 1 vez en el 15, tenemos un entero y sobran 5:

1\frac{5}{10}

5 0
3 years ago
SNOG PLEASE HELP ME! (a+5)(b-3)
Bingel [31]

Answer:

ab-3a+5b-15

Step-by-step explanation:

Once again, FOIL is the way to go!

First, Outside, Inside, Last

ab-3a+5b-15

8 0
3 years ago
Read 2 more answers
Find the perimeter of a rectangle with a length of 6x+3 and a width of -2x-5.
blsea [12.9K]
The simple way of calculating a perimeter is to add all of the sides.
For a rectangle this would equal 2 x length + 2 x width
P = 2(6x + 3) + 2(-2x - 5)
= 12x + 6 - 4x - 10
= 8x - 4

At a higher level both the length and width must be greater than zero (= zero is a trivial rectangle)
6x + 3 > 0
6x > -3
x > -0.5

-2x - 5 > 0
2x + 5 < 0 (multiplying by -1 reverses the inequality)
2x < -5
x < -2.5

This rectangle cannot exist as x cannot be < -2.5 and > -0.5 at the same time!
8 0
3 years ago
Read 2 more answers
Yutaka enjoys running. For every kilometer he runs, he burns 65 calories. He wrote this equation to find how many calories he bu
koban [17]

Answer:

(k): 65k=c   is true  per kilometer he runs,

Step-by-step explanation:

(k): 65k=c   is true     if Yutaka was to walk and burn only 48 calories then k then is x= walk  and y = run   8x+7y>= c      8x+7y>=  8(48) + 7(65) >= 839

5 0
1 year ago
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