the answer 11
Step-by-step explanation:
6+16=22
22÷2=11
Complete Question
If a logo has dimensions of 6 ft and 11ft, he needs a quart of paint for every 22 square ft. How many quarts will he need for the whole logo?
Answer:
3 quarts of paint
Step-by-step explanation:
The Logo is rectangular in shape, hence:
The area of a rectangle = Length × Width
The logo has dimensions of 6 ft and 11ft.
Area of the Logo = 6ft × 11ft = 66ft²
He needs a quart of paint for every 22 square ft
Hence:
22 ft² = 1 quart of paint
66ft² = x
Cross Multiply
22 ft² × x = 66 ft² × 1 quart
x = 66 ft² × 1 quart/22 ft²
x = 3 quarts of paint
Therefore, he will need 3 quarts of paint for the whole logo.
If two secants intersect from a point outside of the circle, then the product of the lengths of the secant and its external segment equals the product of the other secant and its external segment.
#1
5(x+5) = 6(4+6)
5x + 25 = 6 * 10
5x = 60 - 25
5x = 35
x = 7
#2
4(x+4) = 3(5+3)
4x + 16 = 3 * 8
4x = 24 - 16
4x = 8
x = 8/4
x = 2
2x+4=10
2x=6
x=3
2(3)+4= 10
(plus, on parallelograms like that, parallel sides are equal to each other)
