Answer:
-12 bla bla bla bla bla bla bla
Applying the angle addition postulate, the measure of angle ROS is: 16°
<h3>How to Apply the Angle Addition Postulate?</h3>
Given the following angle measures:
m<QOS = 49°
m<POR = 56°
m<POQ = 23°
Find the measure of angle QOR:
m<QOR = m<POR - m<POQ [angle addition postulate]
Substitute the values into the equation
m<QOR = 56 - 23
m<QOR = 33°
Find the measure of angle ROS:
m<ROS = m<QOS - m<QOR [angle addition postulate]
Substitute the values into the equation
m<ROS = 49 - 33
m<ROS = 16°
Therefore, applying the angle addition postulate, the measure of angle ROS is: 16°
Learn more about the angle addition postulate on:
brainly.com/question/24782727
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Answer:
43.33 km
Step-by-step explanation:
<u>Step 1: Find the amount of km Sarah can run in 1 hour</u>
26/3
<u>Step 2: Find the amount of km Sarah ran in 5 hours</u>
26/3 * 5
130/3
43.33
Answer: 43.33 km
Answer:
it helps sharpen ur brain up for future so as not to be cheated by others
Answer:
54 ft^2
(54 in green box; 2 in grey box)
Step-by-step explanation:
We have 2 similar triangles, ABC and DEF.
The area of triangle DEF is given as 6 sq ft.
Side BC of triangle ABC measures 12 ft.
The corresponding side to BC in triangle DEF is EF. It measures 4 ft.
That gives us a scale factor from triangle DEF to triangle ABC.
<em>To find the scale factor between two similar polygons, divide the length of a side of the second polygon by the length of the corresponding side of the first polygon.</em>
scale factor = BC/EF = (12 ft)/(4 ft) = 3
The scale factor of side lengths is 3.
The ratio of the areas is the square of the scale factor.
ratio of areas = 3^2 = 9
Now multiply the area of the first triangle (DEF) by the ratio of areas to get the area of the second triangle (ABC).
area of triangle ABC = 9 * (area of triangle DEF)
area of triangle ABC = 9 * (6 sq ft)
area of triangle ABC = 54 sq ft
Answer: 54 ft^2
(54 in green box; 2 in grey box)
