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3 years ago

In ΔEFG, e = 2.6 cm, f = 7.2 cm and g=8.3 cm. Find the measure of ∠F to the nearest degree.

Mathematics

2 answers:

Svet_ta [14]3 years ago

4 0

Answer:

57°

Step-by-step explanation:

<u>Use the law of cosines:</u>

cos F = (e² + g² - f²)/2eg
cos F = (2.6² + 8.3²- 7.2²)/2(2.6)(8.3)
= 0.5516
∠F = arccos 0.5516
∠F = 57° (rounded to the nearest degree)

goldfiish [28.3K]3 years ago

4 0

Answer:

Step-by-step explanation:

cos F = (e² + g² - f²)/2eg

cos F = (2.6² + 8.3²- 7.2²)/2(2.6)(8.3)

= 0.5516

∠F = arccos 0.5516

∠F = 57° (rounded to the nearest degree)

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