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bija089 [108]
2 years ago
15

In ΔEFG, e = 2.6 cm, f = 7.2 cm and g=8.3 cm. Find the measure of ∠F to the nearest degree.

Mathematics
2 answers:
Svet_ta [14]2 years ago
4 0

Answer:

  • 57°  

Step-by-step explanation:

<u>Use the law of cosines:</u>

  • cos F = (e² + g² - f²)/2eg
  • cos F = (2.6² + 8.3²- 7.2²)/2(2.6)(8.3)
  •          = 0.5516
  • ∠F = arccos 0.5516
  • ∠F = 57° (rounded to the nearest degree)
goldfiish [28.3K]2 years ago
4 0

Answer:

57

Step-by-step explanation:

cos F = (e² + g² - f²)/2eg

cos F = (2.6² + 8.3²- 7.2²)/2(2.6)(8.3)

        = 0.5516

∠F = arccos 0.5516

∠F = 57° (rounded to the nearest degree)

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Answer:

Step-by-step explanation:

 

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Now lets substitute (-3s + 0.75) into the first equation for z, then solve for s:

 

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meriva

Answer:

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