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2 years ago

QUESTION ON PIC THANK YOU FOR ANSWERING

Mathematics

1 answer:

katen-ka-za [31]2 years ago

6 0

For a square, you can check off the first 3. For a rhombus, you can check off the first and third box. For a parallelogram, you can check the third box

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Find the value of APD angle.

Maslowich

Answer:

135

Step-by-step explanation:

angle APB is an alternate interior angle to DBC and line DB is supplementary

APD=180-45=135

7 0

3 years ago

PLEASE HELPPP MEEEEEEEEEEEEEEE

Papessa [141]

The answer would be

4d+2.75p=12

7 0

3 years ago

Read 2 more answers

Use the figure. Help me with this please

defon

The answer is C: 4.4

It might be A at the same time tho LMOO

4 0

3 years ago

A die is rolled one thousand times. The percentage of aces should be around ____ or so. the first step iin computing this proble

Katyanochek1 [597]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Please find the complete question in the attached file.

$Box \ average =\frac{1}{6} \\\\SD = \frac{1}{6} \times \frac{5}{6} = \frac{5}{36} \approx 0.373\\\\Expected \ value= 1000 \times \frac{1}{6} \approx 166.7\\\\SE = 1000 \times 0.373 \approx 11.8\\\\$

The total number of aces is approximately 167, 12 or more. The SE is 12 out of 1000, which is 1.2 percent.

The percentage of aces is expected to be around 16.67% , or 1.2%.

7 0

3 years ago

fter production, a computer component is given a quality score of A, B, and C. On the average U of the components were given a q

RoseWind [281]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

In the given question some of the data is missing so, its correct question is defined in the attached file please find it.

Let

A is quality score of A

B is quality score of B

C is quality score of C

$\to P[A] =0.55\\\\\to P[B] =0.28\\\\\to P[C] =0.17\\$

Let F is a value of the content so, the value is:

$\to P[\frac{F}{A}] =0.15\\\\\to P[\frac{F}{B}] =0.12\\\\\to P[\frac{F}{C}] =0.14\\$

Now, we calculate the tooling value:

$\to p[\frac{C}{F}]$

using the baues therom:

$\to p[\frac{C}{F}] = \frac{p[C] \times p[\frac{F}{C} ]}{p[A] \times p[\frac{F}{A}] + p[B] \times p[\frac{F}{B}]+p[C] \times p[\frac{F}{C}] }$

$= \frac{ 0.17 \times 0.14 }{0.55 \times 0.15 + 0.28 \times 0.12 + 0.17 \times 0.14 } \\\\= \frac{0.0238}{0.0825 + 0.0336 + 0.0238} \\\\= \frac{0.0238}{0.1399} \\\\=0.1701$

7 0

3 years ago