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Margarita [4]
3 years ago
12

A carnival charges $1.50 per ride after an entrance fee. You paid a total of $30

Mathematics
1 answer:
Murljashka [212]3 years ago
3 0

Answer:yeah❤

Step-by-step explanation:

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16.872 divided by 0.24<br><br><br> HELP I NEED HELP QUICJ
goldenfox [79]

Answer:

70.3

Step-by-step explanation:

16.872/.24= 70.3

6 0
3 years ago
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a previous analysis of paper boxes showed that the standard deviation of their lengths is 15 millimeters. A packers wishes to fi
vladimir1956 [14]

Answer:

864.36 boxes

Step-by-step explanation:

In the question above, we are given the following values,

Confidence interval 95%

Since we know the confidence interval, we can find the score.

Z score = 1.96

σ , Standards deviation = 15mm

Margin of error = 1 mm

The formula to use to solve the above question is given as:

No of boxes =[ (z score × standard deviation)/ margin of error]²

No of boxes = [(1.96 × 15)/1]²

= 864.36 boxes

Based on the options above, we can round it up to 97 boxes.

8 0
3 years ago
Breifly describe the rules of multiplying and dividing integers
Ivan

Answer:

Just multiply the absolute values and make the answer positive. When you multiply two integers with different signs, the result is always negative. Just multiply the absolute values and make the answer negative. When you divide two integers with the same sign, the result is always positive.

Step-by-step explanation:

6 0
3 years ago
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2. The set of whole number from 1 to 20
slega [8]

Answer:

c:2,4,6,8,10,12,14,16,18,20

Step-by-step explanation:

set d:4,8,13,15,20

6 0
3 years ago
Life tests performed on a sample of 13 batteries of a new model indicated: (1) an average life of 75 months, and (2) a standard
Alja [10]

Answer:

The lower limit of the 90% confidence interval for the population mean life of the new model is 72.53 months.

Step-by-step explanation:

Our sample size is 13.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 13-1 = 12

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.90}{2} = \frac{0.10}{2} = 0.05

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 12 and 0.05 in the t-distribution table, we have T = 1.782.

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{5}{\sqrt{13}} = 1.3868

Now, we multiply T and s

M = T*s = 1.782*1.3868 = 2.47

The lower end of the interval is the mean subtracted by M. So it is 75 - 2.47 = 72.53

The lower limit of the 90% confidence interval for the population mean life of the new model is 72.53 months.

5 0
3 years ago
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