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2 years ago

4. A rectangular field has a perimeter of 300m. What is the area of the field if the length of

Mathematics

1 answer:

USPshnik [31]2 years ago

5 0

Answer:

Step-by-step explanation:

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What is the other endpoint if one endpoint is (10,12) and the midpoint is (6,9).?

Lubov Fominskaja [6]

Answer:

$(2,\, 6)$ .

Step-by-step explanation:

Let $(x_{0},\, y_{0})$ and $(x_{1},\, y_{1})$ denote the two endpoints.

The formula for the midpoint of these two points would be:

$\displaystyle \left(\frac{x_{0} + x_{1}}{2},\, \frac{y_{0} + y_{1}}{2}\right)$ .

(Similar to taking the average of each coordinate.)

In this question, it is given that $x_{0} = 10$ whereas $y_{0} = 12$ . Substitute these two values into the expression for the coordinate of the midpoint:

$x$ -coordinate of the midpoint: $\displaystyle \frac{10 + x_{1}}{2} = 6$ .
$y$ -coordinate of the midpoint: $\displaystyle \frac{12 + y_{1}}{2} = 9$ .

Solve these two equations for $x_{1}$ and $y_{1}$ : $x_{1} = 2$ whereas $y_{1} = 6$ .

Hence, the coordinate of the other point would be $(2,\, 6)$ .

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2 years ago

V^2+2=8-4v^2 solve the question algebically

iris [78.8K]

Answer:

v = ± sqrt(6/5)

Step-by-step explanation:

v^2+2=8-4v^2

Add 4v^2 to each side

v^2+ 4v^2+2=8-4v^2+ 4v^2

5v^2 +2 = 8

Subtract 2 from each side

5v^2 +2-2 = 8-2

5 v^2 = 6

Divide each side by 5

5v^2 /5 = 6/5

v^2 = 6/5

Take the square root of each side

sqrt(v^2) = ± sqrt(6/5)

v = ± sqrt(6/5)

8 0

2 years ago

Read 2 more answers

Please help me with this I need the right answer

Grace [21]

Answer:

B is the correct answer.

Step-by-step explanation:

graph attached below, with red as the parent function (f(x)=3^x) and blue as the change (f(x)=3^x-8).

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2 years ago

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In a volatile housing market, the overall value of a home can be modeled by V(x) = 210x2 – 4400x + 125000, where V represents th

Grace [21]

Answer:

I think a picture can explain better than me!

Step-by-step explanation:

Have a good day.

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2 years ago

A rectangle has a length that is three feet more than twice it's width. The perimeter of the rectangle is 78 feet. State the val

ivann1987 [24]

Let the width of the rectangle be 'w'

According to the question length of the rectangle (l) is three feet more than twice it's width;

$\longrightarrow$ l = (2w + 3) ft

Perimeter of rectangle = 78 ft

Formula of perimeter of rectangle = 2(Length + Width)

So,

$\rm \implies 2(Length + Width) = 78 \\ \\ \rm \implies 2(2w + 3 + w) = 78 \\ \\ \rm \implies 2(3w + 3) = 78 \\ \\ \rm \implies 2 \times 3(w + 1) = 78 \\ \\ \rm \implies 6(w + 1) = 78 \\ \\ \rm \implies w + 1 = \dfrac{78}{6} \\ \\ \rm \implies w + 1 = 13 \\ \\ \rm \implies w = 13 - 1 \\ \\ \rm \implies w = 12 \: ft$

$\therefore$ Width of the rectangle (w) = 12 ft

3 0

2 years ago