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Grace [21]
2 years ago
12

Which expression is equivalent to 18x^2√14x^8 / 6√7x^4, if x ≠ 0?

Mathematics
1 answer:
Marizza181 [45]2 years ago
6 0

The equivalent expression of 18x^2\sqrt{14x^8} \div 6\sqrt{7x^4} is 3x^4\sqrt{2}

<h3>How to determine the equivalent expression?</h3>

The expression is given as:

18x^2\sqrt{14x^8} \div 6\sqrt{7x^4}

Start by dividing 18 by 6

3x^2\sqrt{14x^8} \div \sqrt{7x^4}

Next, divide 14 by 7

3x^2\sqrt{2x^8} \div \sqrt{x^4}

Take the square root of x^8 and x^4

3x^2 * x^4\sqrt{2} \div x^2

Divide x^2 by x^2

3* x^4\sqrt{2}

Evaluate

3x^4\sqrt{2}

Hence, the equivalent expression of 18x^2\sqrt{14x^8} \div 6\sqrt{7x^4} is 3x^4\sqrt{2}

Read more about equivalent expression at:

brainly.com/question/2972832

#SPJ1

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-2(2x+3)=-4(x+1) - 2
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Answer:

All real numbers are solutions

Step-by-step explanation:

Let's solve your equation step-by-step.

−2(2x+3)=−4(x+1)−2

Step 1: Simplify both sides of the equation.

−2(2x+3)=−4(x+1)−2

(−2)(2x)+(−2)(3)=(−4)(x)+(−4)(1)+−2(Distribute)

−4x+−6=−4x+−4+−2

−4x−6=(−4x)+(−4+−2)(Combine Like Terms)

−4x−6=−4x+−6

−4x−6=−4x−6

Step 2: Add 4x to both sides.

−4x−6+4x=−4x−6+4x

−6=−6

Step 3: Add 6 to both sides.

−6+6=−6+6

0=0

Answer:

All real numbers are solutions.

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Find all the zeros of the equation<br> -3x^4 + 27x^2 + 1200 = 0
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Answer:

\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i

Step-by-step explanation:

Biquadratic Equation

It's a fourth-degree equation where the terms of degree 1 and 3 are missing. It can be solved for the variable squared as if it was a second-degree equation, and then take the square root of the results

Our equation is

\displaystyle -3x^4+27x^2+1200=0

If we call y=x^2, our equation becomes a second-degree equation

\displaystyle -3y^2+27y+1200=0

Dividing by -3

\displaystyle y^2-9y-400=0

Factoring

\displaystyle (y-25)(y+16)=0

It leads to these solutions

\displaystyle y=25\ ,\ y=-16

Taking back the change of variable, we have for the first solution

\displaystyle x^2=25\Rightarrow x=-5,x=5

Now for the second solution, we get imaginary (complex) values

\displaystyle x^2=-16\Rightarrow x=4i,\ x=-4i

Summarizing, the four solutions for x are

\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i

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