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3 years ago

4= t/2.5 t=? this is mathematics

Mathematics

2 answers:

nirvana33 [79]3 years ago

6 0

Answer:

4=t/2.5

*2.5 on both sides

10=t

Hope this helps!

-mark as brianliest-

taurus [48]3 years ago

4 0

Answer:

Step-by-step explanation:

$4=\dfrac{t}{2.5}\qquad\text{multiply both sides by 2.5}\\\\4\cdot2.5=\dfrac{t}{2.5\!\!\!\!\!\diagup}\cdot2.5\!\!\!\!\!\diagup\qquad\text{cancel 2.5}\\\\10=t\to t=10\\\\\text{Check:}\\\\\dfrac{10}{2.5}=4\qquad\bold{CORRECT}$

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marusya05 [52]

Answer:

Yes there is sufficient evidence.

Null hypothesis; H_o ; μ = 445

Alternative hypothesis; H_o ; μ ≠ 445

Step-by-step explanation:

The null hypothesis states that there is no difference in the test which is denoted by H_o. However, the sign of null hypothesis is denoted by the signs of = or ≥ or ≤.

Meanwhile, the alternative hypothesis is one that defers from the null hypothesis. This therefore implies a significant difference in the test. Thus, the signs of alternative hypothesis is denoted by; < or > or ≠.

Now, the question we have is a two tailed test. Thus;

The null hypothesis is;

bag filling machine works correctly at the 445 gram setting which is;

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bag filling machine works incorrectly at the 445 gram setting which is;

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3 years ago

24 x 12 1/2 x 12 3/4 what is the volume of the fish tank

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Answer:

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Step-by-step explanation:

To find the volume of the fish tank multiply out the dimensions.

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For example, the following sequences are arithmetic:

1, 2, 3, 4, 5, 6, ... (difference = 1)

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2. Carla's sequence is not arithmetic, because the differences between consecutive terms are all different:

13 - 11 = 2

17 - 13 = 4

25 - 17 = 8

She can adjust the sequence by changing the last two numbers to 15 and 17, since this makes the difference fixed:

13 - 11 = 2

15 - 13 = 2

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and so on.

3. The sequence

45, 48, 51, 54, ...

is arithmetic with difference 3 between terms. Recursively, we can write the $n$ th term, $a_n$ , in terms of the previous, $(n-1)$ th term, $a_{n-1}$ :

$a_n=a_{n-1}+3$

By this definition, we can just as easily write the $(n-1)$ th term in terms of the $(n-2)$ th term:

$a_{n-1}=a_{n-2}+3$

Then, substituting this into the previous equation, we have

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We can continue this process to write $a_n$ in terms of $a_1$ :

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$a_{n-3}=a_{n-4}+3\implies a_n=a_{n-4}+4\cdot3$

and so on. (You might notice that the subscript of the term on the right side, and the number of 3s being added, together sum to $n$ .) The pattern continues down to

$a_n=a_1+(n-1)\cdot3$