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2 years ago

When does a driver have to stop for a school bus

1 answer:

4 0

A driver have to stop for a school bus when the red lights are flashing and there is no barrier between his/her vehicle and the bus.

<h3>What are traffic rules?</h3>

Traffic rules are rules that are expected to follow by the road users for the safety of everyone using the road.

For instance, when the red lights are flashing , it simply means to stop, while the green light means that the vehicle can continue to move, and yellow light means to be at alert to move.

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8. An object accelerates 12.0 m/s2 when a force of 6.0 newtons is applied to it. What is the mass of the object? _______________

Sholpan [36]

Answer:

Mass of object is 0.5kg

Explanation:

Given the following data;

Force = 6N

Acceleration = 12m/s²

Mass =?

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

$F = ma$

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Making mass (m) the subject, we have;

$Mass (m) = \frac{F}{a}$

Substituting into the equation;

$Mass (m) = \frac{6}{12}$

Mass, m = 0.5kg.

Therefore, the mass of the object is 0.5kg

5 0

3 years ago

A larger object is made of two balls separated by a massless rigid rod that is 1.5 m long. The mass of the red ball at one end i

lions [1.4K]

Answer:

The speed of the 1 kg red ball 8.04 m/s .

Explanation:

Given :

Separation between rods , d = 1.5 m .

Mass of the red ball is 1 kg .

Mass of the orange ball is 5.7 kg .

Angular velocity , $\omega=1\ rev/s = 2\pi\ rad/s$ .

Now , distance of center of mass from red ball is :

$r =\dfrac{0\times 1+1.5\times 5.7}{1+5.7}\\\\r = 1.28\ m$

We know , speed is given by :

$v=\omega r\\\\v=2 \times \pi \times 1.28\\\\v=8.04\ m/s$

Hence , this is the required solution .

5 0

3 years ago

Two friends whisper at a volume of 20 decibels. Later, they converse at a volume of 40 decibels.

Yuki888 [10]

40 dB is 20 dB more power than 20 dB is. 20 dB more means 100 times as much.

4 0

3 years ago

Read 2 more answers

1) A ball is dropped from the Eiffel Tower (300 m), how long would it take for the ball to reach a velocity of 65 m/s? How far d

Andreas93 [3]

Answer:

Explanation:

If you drop a ball from

the top of a building it

gains speed as it falls.

• Every second, its

speed increases by

10 m/s.

• Also it does not fall

equal distances in

equal time intervals

• If the acceleration = 0 then the velocity is

constant. [remember that acceleration is

the rate of change of velocity]

• In this case the distance an object will

travel in a certain amount of time is given

by distance = velocity x time

• For example, if you drive at 60 mph for

one hour you go 60 mph x 1 hr = 60 mi.

6 0

3 years ago

Problem 13.175 A 1-kg block B is moving with a velocity v0 of magnitude as it hits the 0.5-kg sphere A, which is at rest and han

Svetradugi [14.3K]

Explanation:

Mass of the Block, Mb = 1.0 kg Initial Velocity of Block, Vb = 2.0 m/s

Mass of the Ball, Ma = 0.5 kg Coefficient of Kinetic Friction, μ = 0.6

Coefficient of Restitution, e = 0.8 Gravity = 9.81 m/s^2

Sum of the forces of the X-axis components and Y-axis components are:

∑ Fx = Ff = Mb × a

Equation for frictional force,

Ff = μ × N

∑ Fy = N - mb × g = 0

Note:

N = mb × g

Therefore, to solve for the acceleration, we have:

μ × Mb × g = Mb × a

a = μ × g

= 0.6 × 9.81

= 5.88 m/s^2

Therefore, ratio of velocities using the coefficient of restitution, e:

e = (Vb2 – Va1)/ (Va – Vb)

Note: Va = zero (initially at rest)

Va2 – Vb2 = 0.8 × ( 0 - 2 m/s)

Vb2 – Va2 = -1.6 m/s

Vb2 = a2 – 1.6

Using Conservation of Momentum Equation:

Ma × Va + Mb × Vb = Ma × Va2 + Mb × Vb2

0 + 1kg × 2 m/s = 0.5 kg × Va2 + 1 kg × Vb2

Vb2 = 2 - 0.5 × Va2

Substitute in Vb2,

1.5 × Va2 = 3.6

Va2 = 2.4 m/s

Vbs = 0.8 m/s

mgh = 0.5 × Mv2

h = v2/ 2g

h = 0.294 m

Using equation of motion,

Vf^2 = Vo^2 + 2a × S

Given:

Vf = 0 m/s

a = 5.88 m/s^2

0 = 0.82 + 2(5.88) × ΔS

Δx = 0.0544 m

4 0

3 years ago