When does a driver have to stop for a school bus
1 answer:
You might be interested in
Answer:
Acceleration = 10.06 m/s²
Explanation:
1 mile = 1.6093km
1609.3m = 1 mile
1 m = mile
50.0 miles/hour = m/s
= 22.35m/s
from equation
S = Ut + 1/2 at²
v = U + at
22.35 = 0 + a * 2.22
a = 22.35 ÷ 2.22
= 10.06 m/s²
The third equation of free fall can be applied to determine the acceleration. So that Paola's acceleration during the flight is 39.80 m/.
Acceleration is a quantity that has a direct relationship with velocity and also inversely proportional to the time taken. It is a vector quantity.
To determine Paola's acceleration, the third equation of free fall is appropriate.
i.e =
± 2as
where: V is the final velocity, U is the initial velocity, a is the acceleration, and s is the distance covered.
From the given question, s = 20.1 cm (0.201 m), U = 4.0 m/s, V = 0.
So that since Poala flies against gravity, then we have:
=
- 2as
0 = - 2(a x 0.201)
= 16 - 0.402a
0.402a = 16
a =
= 39.801
a = 39.80 m/
Therefore Paola's acceleration is 39.80 m/.