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Sedbober [7]
3 years ago
10

Consider the activity and specificity of the three enzymes. Pepsin is most active in the human ________ and helps to digest ____

______.

Physics
2 answers:
maksim [4K]3 years ago
8 0
I would have to say stomach and proteins. <span />
jeka943 years ago
5 0

Answer:

"Consider the activity and specificity of the three enzymes. Pepsin is most active in the human<u> Stomach or gut </u>and helps to digest<u>  proteins</u>."

<u>Types of Enzymes:</u>

  1. <u>Amylase:</u>For the breakdown of the carbohydrate macro molecules in to small molecules, the amylase is present in the stomach of the human beings and other living beings who ingest the carbohydrates.
  2. <u>Lipase: </u>For, the break down of the lipid molecules(fatty acids and waxes) we have the lipase inside the gut or stomach of the living beings.
  3. <u>Pepsin:</u> The pepsin is secreted inside the gut or stomach of the living beings to digest the protein molecules, changing them into small forms of the basic structural units known as the amino acids.

Explanation:

<u>Enzymes: </u>

The chemical components or molecules that are required to speed up the reactions that happens inside the living body. They are important because with out the presence of the enzyme there will be less cellular activities and we will have less productivity inside our body.

<u>Pepsin:</u>

The pepsin is present and secreted by the mucus layer and the chief cells that are found in the stomach's layers. While, they are present in the gastric juices of the stomach for better digestion of the food molecules.

While it is present or secreted for the digestion of the proteins molecules. As the macro molecules are changed into smaller amino acids for the proper digestion. As the pepsin is found inside the gut or stomach of the different mammals, birds,and other living beings

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Answer:

Second option 6.3 N at 162° counterclockwise from  

F1->

Explanation:

Observe the attached image. We must calculate the sum of all the forces in the direction x and in the direction y and equal the sum of the forces to 0.

For the address x we have:

-F_3sin(b) + F_1 = 0

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We have 2 unknowns (F_3 and b) and we have 2 equations.

Now we clear F_3 from the second equation and introduce it into the first equation.

F_3 = \frac{F_2}{cos (b)}

Then

-\frac{F_2}{cos (b)}sin(b)+F_1 = 0\\\\F_1 = \frac{F_2}{cos (b)}sin(b)\\\\F_1 = F_2tan(b)\\\\tan(b) = \frac{F_1}{F_2}\\\\tan(b) = \frac{5.7}{1.9}\\\\tan^{-1}(\frac{5.7}{1.9}) = b\\\\b= 72\°\\\\m = b +90\\\\\m= 162\°

Then we find the value of F_3

F_3 = \frac{F_1}{sin(b)}\\\\F_3 =\frac{5.7}{sin(72\°)}\\\\F_3 = 6.01 N

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kow [346]

Answer:

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Explanation:

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