While working out, a man performed 200 J of work in 3 seconds. What was
1 answer:
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Answer:
Distance, d = 112.5 meters
Explanation:
Initially, the bicyclist is at rest, u = 0
Final speed of the bicyclist, v = 30 m/s
Acceleration of the bicycle,
Let s is the distance travelled by the bicyclist. The third equation of motion is given as :
s = 112.5 meters
So, the distance travelled by the bicyclist is 112.5 meters. Hence, this is the required solution.