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Gre4nikov [31]
3 years ago
7

While working out, a man performed 200 J of work in 3 seconds. What was

Physics
1 answer:
svetlana [45]3 years ago
7 0
The answer is b because I just know it is
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Oop i spill grape jucie on the carpet my mom gonna kill me :(
Free_Kalibri [48]

Answer:

Wow that is tough. Go hide lol

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3 years ago
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Calculate the inhomogeneity of a 1.5 t magnet
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3 years ago
The diagram shows the electric field around two charged objects.
anyanavicka [17]

Here we have been given two charged body W and X.

We are asked to determine the nature of charge.

Before coming into conclusion, first we have to understand the electric field lines.

The electric field lines are pictorial representation of imaginary lines which are drawn to denote the electric field in a graphical  way.

The electric field line starts from a positive charge and ends at a negative charge.It means for positive charges the electric field lines are outward and for negative charges the filed lines will be inward.

In the given diagram,the filed lines for W is towards W itself.The same is also in case of X.

Hence both the charges must be negative in nature.

Hence the correct answer to the question will be B i.e W negative and X: NEGATIVE.

8 0
3 years ago
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A ball rolls 60 centimeters along a sidewalk in 5 seconds what is the speed of the ball.
meriva

Answer:

12 cm/s

Explanation:

Quite simply, you are looking for  cm/s

  so   60 cm / 5s   = 12 cm/s

6 0
2 years ago
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A cylindrical tungsten filament 16.0 cm long with a diameter of 1.00 mm is to be used in a machine for which the temperature wil
KonstantinChe [14]

Answer:

Explanation:

Resistance of the tungsten wire

R = resistivity x length / cross sectional area

= \frac{5.25\times10^{-8}\times16\times10^{-2}}{3.14\times(.5\times10^{-3})^2}

= 107 x 10⁻⁴ ohm

Resistance at 120 degree can be obtained from the following formula

R_t = R_0( 1 + \alpha\times t )

R_t = 107\times10^{-4}( 1 + .0045\times 100)

= 155.15 x 10⁻⁴ ohm

= 160 x 10⁻⁴ ohm ( rounding off to two syg fig )

current = 12.5

potential diff = 12.5 x 155.15 x 10⁻⁴ V

=  0 .1939 V

= .19 V

required electric field = potential diff / length of wire

= .1939 / 16 x 10⁻²

= 1.2 N / C

4 0
3 years ago
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