While working out, a man performed 200 J of work in 3 seconds. What was
1 answer:
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Answer:
Centripetal acceleration = 83.77m/s²
Explanation:
<u>Given the following data;</u>
Radius, r = 0.13m
Velocity, v = 3.3m/s
To find centripetal acceleration;
Centripetal acceleration is given by the formula;
Substituting into the equation, we have;
<em>Centripetal acceleration = 83.77m/s²</em>
<em>Therefore, the centripetal acceleration of the edge of the disc is 83.77 m/s². </em>
Answer:
The value is
Explanation:
From the question we are told that
The initial speed is
Generally the total energy possessed by the space probe when on earth is mathematically represented as
Here is the kinetic energy of the space probe due to its initial speed which is mathematically represented as
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And is the kinetic energy that the space probe requires to escape the Earth's gravitational pull , this is mathematically represented as
Here is the escape velocity from earth which has a value
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Generally given that at a position that is very far from the earth that the is Zero, the kinetic energy at that position is mathematically represented as
Generally from the law energy conservation we have that
So
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