Answer:
12.0 meters
Explanation:
Given:
v₀ = 0 m/s
a₁ = 0.281 m/s²
t₁ = 5.44 s
a₂ = 1.43 m/s²
t₂ = 2.42 s
Find: x
First, find the velocity reached at the end of the first acceleration.
v = at + v₀
v = (0.281 m/s²) (5.44 s) + 0 m/s
v = 1.53 m/s
Next, find the position reached at the end of the first acceleration.
x = x₀ + v₀ t + ½ at²
x = 0 m + (0 m/s) (5.44 s) + ½ (0.281 m/s²) (5.44 s)²
x = 4.16 m
Finally, find the position reached at the end of the second acceleration.
x = x₀ + v₀ t + ½ at²
x = 4.16 m + (1.53 m/s) (2.42 s) + ½ (1.43 m/s²) (2.42 s)²
x = 12.0 m
Answer:
Explanation:
Given
Power Supplied ![[tex]P_{input}=4\ kW](https://tex.z-dn.net/?f=%5Btex%5DP_%7Binput%7D%3D4%5C%20kW)
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Efficiency of the motor 
and 
So, vacuum cleaner delivers a power of
Answer:
Power = 13.5744 kilowatts
Explanation:
Power is the rate at which work is done. ... Great power means a large amount of work or energy developed in a short time. For example, when a powerful car accelerates rapidly, it does a large amount of work and consumes a large amount of fuel in a short time.
Formula for power = work/time
= IVT/T
= IV
Where I is the current
And V is the voltage
The voltage V supply = 168 v
The current A supply = 80.8 A
Power = 80.8*168
Power = 13574.4 watts
Power = 13.5744 kilowatts
Answer:
Explanation:
In order to calculate the equivalent spring constant we need to use the next formula:
Replacing the data provided:
Finally, to calculate the frequency of oscillation we use this:
Replacing m and k:
Answer: Diagram B
Explanation:
A free body diagram shows the forces acting on an object in a certain scenario.
In this scenario there are two forces acting on the carrot: the Tension force (Ft) from the rope that the carrot is hanging from and Gravitational force(Fg) which is pulling the carrot to the Earth.
The diagram depicting this is diagram B.
