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Orlov [11]
3 years ago
6

A larger object is made of two balls separated by a massless rigid rod that is 1.5 m long. The mass of the red ball at one end i

s 1 kg and the mass of the orange ball at the other end is 5.7 kg. As in example 12.1, the balls are rotating about the center of mass. Calculate the speed of the 1 kg red ball if the angular velocity is 1 rev/s.
Physics
1 answer:
lions [1.4K]3 years ago
5 0

Answer:

The speed of the 1 kg red ball 8.04 m/s .

Explanation:

Given :

Separation between rods , d = 1.5 m .

Mass of the red ball is 1 kg .

Mass of the orange ball is 5.7 kg .

Angular velocity , \omega=1\ rev/s = 2\pi\ rad/s .

Now , distance of center of mass  from red ball is :

r =\dfrac{0\times 1+1.5\times 5.7}{1+5.7}\\\\r = 1.28\ m

We know , speed is given by :

v=\omega r\\\\v=2 \times \pi \times  1.28\\\\v=8.04\ m/s

Hence , this is the required solution .

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Explanation:

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For the sample of mercury in this problem we have

Q = 275 J

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When an object is placed 110 cm from a diverging thin lens, its image is found to be 55 cm from the lens. The lens is removed, a
Kazeer [188]

Explanation:

Given that,

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The focal length of the diverging lens is 36.6 cm.

Now given a thin lens with same magnitude of focal length 36.6 cm is replaced.    

Here, The object distance is again the same.

We need to calculate the image distance for converging lens

Using formula of lens

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Answer:

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Explanation:

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Answer:

\boxed {\boxed {\sf D. \ 6.02*10^{23} \ atoms}}

Explanation:

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3 years ago
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