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svlad2 [7]
3 years ago
13

The circumference of great circle of a hemisphere is 44 cm. find the total surface area of the hemisphere​

Mathematics
1 answer:
max2010maxim [7]3 years ago
6 0

Answer:

I didn't know if you meant that the circumference of tje hemisphere was 44 or if the circumference of the cirkel in which the hemisphere exists is 44 but you rearrange the numbers.

Step-by-step explanation:

The formula for calculating a circumference is 2×pi×r, with r as tje radius of the cirkel. So in this instance we get 2×pi×r=44. r=44/(2×pi)=7.00 centimeters. The total surface area of a cirkel=pi×r^2=pi×7.00^2=154.06 meters squared. 154.06/2=77.03 meters squared (hemisphere is half of a cirkel)

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denpristay [2]

Answer:

12.76

Step-by-step explanation:

This is much easier to solve if you draw it out on a graph. The perimeter is the sum of all the sides. I used the Pythagorean theorem to find the hypotenuse.

{a}^{2}  +  {b}^{2}  =  {c}^{2}  \\ c =  \sqrt{ {a}^{2} +  {b}^{2}  }

dc =  \sqrt{ {3}^{2}  +  {1}^{2} }  =  \sqrt{10}  \\  cf = 1 \\ fe =  \sqrt{ {4}^{2}  +  {2}^{2} }  =  \sqrt{20}  \\ de =  \sqrt{ {1}^{2} +  {4}^{2}  }  =  \sqrt{17}  \\  \sqrt{10}  + 1 +  \sqrt{20}  +  \sqrt{17}  = 12.76

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3 years ago
Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

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c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

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e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

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