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jarptica [38.1K]
3 years ago
14

Does Someone Know How To do this???????/

Mathematics
2 answers:
Kaylis [27]3 years ago
7 0

Answer:

Yea so it's 2x + 14 ..

Step-by-step explanation:

Just plug x + 5 into h(x):

h(x + 5) = 2(x + 5) + 4 =

Factor: 2x + 10

Then add 4 to 10 = 14

So the final answer is 2x+14..hope this helps :D

geniusboy [140]3 years ago
4 0

Answer:

2x + 14

Step-by-step explanation:

To evaluate h(x + 5) substitute x = x + 5 into h(x), that is

h(x + 5) = 2(x + 5) + 4 = 2x + 10 + 4 = 2x + 14

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Y = x + z<br><br> solve for x
stepladder [879]

Answer:

Step-by-step explanation:

X=Y+Z

4 0
2 years ago
A lacrosse player throws a ball into the air from a height of 6 feet with an initial vertical velocity of 64 feet per second. Wh
-Dominant- [34]

Answer:

Step-by-step explanation:

I'm going to use calculus to solve this, because it's the simplest way.  

The acceleration due to gravity in feet is the second derivative of the position function.  We will start with the acceleration and work backwards with antiderivatives to get to the position function.

a(t) = -32.  Going backwards and using the fact that the initial vertical velocity is 64 ft/sec, our velocity function is

v(t) = -32t + 64.  Going backwards and using the fact that the initial height of the ball is 6 feet, our position function is

s(t)=-16t^2+64t+6

The first part of this question asks us the maximum height of the ball.  From Physics, we learn that the maximum height of a projectile is reached when the velocity is 0, which happens to be right where the projectile stops for a nanosecond in the air to turn around and come back down.  We set the velocity function equal to 0 and solve for t.

0 = -32t + 64 and

0 = -32(t - 2).  By the Zero Product Property, either -32 = 0 or t - 2 = 0.  It's obvious that -32 does not equal 0, so t - 2 must equal 0.  Solving this for t:

t - 2 = 0 so

t = 2 seconds.  Since the maximum height is reached at a time of 2 seconds, we plug 2 seconds into the position function to get its position at 2 seconds (which is also the max height of the ball).

s(2)=-16(2)^2+64(2)+6 and

s(2) = -64 + 128 + 6 so

s(2) = 70 feet

Now we want to know when the ball will hit the ground.  "When" is a time value, and we know that the height of the ball on the ground is 0, so we sub in a 0 for s(t) and factor the quadratic.

Using the quadratic formula:

t=\frac{-64+/-\sqrt{4096-4(-16)(6)} }{-32} and

t=\frac{-64+/-\sqrt{4480} }{-32} which gives us the 2 solutions

t=\frac{-64+\sqrt{4480} }{-32} and

t=\frac{-64-\sqrt{4480} }{-32}

Plugging into your calculator, the first t = -.0916500 and the second t = 4.091

We all know that time cannot ever be negative, so our t value is 4.09.

Again, from Physics, we know that a projectile reaches it max height at halfway through its travels, so it just goes to follow logically that if it halfway through its travels at 2 seconds, then it will hit the ground at 4 seconds.  And it does!! How awesome is that?!

4 0
3 years ago
Given that A=27, B=43 and c=17, solve triangle ABC to the nearest hundredth
katrin2010 [14]
When we are given 3 sides, we try to solve the angles first by using the
law of cosines
cos (A) = [b^2 + c^2 - a^2] / (2 * b * c)
cos (A) = [43^2 + 17^2 -27^2] / (2 * 43 * 17)
cos (A) = [1,849 + 289 -729] / <span> <span> <span> 1,462
</span></span></span>cos (A) = 1,409 / 1,462
cos (A) = <span> <span> <span> 0.96374829001368
Angle A = 15.475

Now that we have one angle, we next can use the
Law of Sines
sin(B) / side b = sin(A) / side a
sin(B) = sin(A) * sideb / sidea
</span></span></span><span>sin(B) = sin(15.475) * 43 / 27
</span><span>sin(B) = 0.26682 * 43 / 27
sin (B) = </span><span>0.424935555555</span>
Angle B = 25.147 Degrees
Remember the arc sine (<span>0.424935555555) also equals </span> <span> <span> <span> 154.85

</span></span></span>Finally, calculating the third angle is quite easy
Angle C =  180 - Angle (A) - Angle(B)
Angle C =  180 - 15.475 - 154.85
Angle C =  9.675

Source:
http://www.1728.org/trigtut2.htm


6 0
2 years ago
Need help can someone help me
Hunter-Best [27]

The absolute value of B is 1 3/5 because although B is in the negatives, absolute value makes it positive.

7 0
2 years ago
Read 2 more answers
Carson can choose one vehicle (car or truck), one color (blue, red, or silver), and one type of transmission (standard or automa
77julia77 [94]

Answer:

12 possible outcomes

Step-by-step explanation:

Choosing 1 vehicle from 2 = 2C1 = 2

Choosing 1 color from 3 = 3C1 = 3

Choosing 1 type from 2 = 2C1 = 2

Number of possible outcomes :

2C1 * 3C1 * 2C1

2 * 3 * 2

= 12 different possible outcomes

5 0
2 years ago
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