\begin{gathered}\{\begin{array}{ccc}3x+5y=2&|\cdot(-3)\\9x+11y=14\end{array}\\\underline{+\{\begin{array}{ccc}-9x-15y=-6\\9x+11y=14\end{array}}\ \ |\text{add both sides of equations}\\.\ \ \ \ \ -4y=8\ \ \ |:(=4)\\.\ \ \ \ \ y=-2\\\\\text{substitute the value of y to the first equation}\\\\3x+5\cdot(-2)=2\\3x-10=2\ \ \ |+10\\3x=12\ \ \ |:3\\x=4\\\\Answer:\ x=4;\ y=-2\to(4;\ -2)\end{gathered}
{
3x+5y=2
9x+11y=14
∣⋅(−3)
−9x−15y=−6
9x+11y=14
add both sides of equations
. −4y=8 ∣:(=4)
. y=−2
substitute the value of y to the first equation
3x+5⋅(−2)=2
3x−10=2 ∣+10
3x=12 ∣:3
x=4
Answer: x=4; y=−2→(4; −2)
Answer:
<h2>YES</h2>
Step-by-step explanation:
If the number is rational, I can write it as a fraction in which the numerator and denominator are integers (denominator other than 0).
If is repeating:
<em>multiply both sides by 10</em>
<em> make the difference 10x - x</em>
<em>divide both sides by 9</em>
Fourty million, twenty-three thousand, thirty-two.
40,000,000 + 20,000 + 3,000 + 30 + 2
An integer is any whole number (not fractions) that can be either negative or positive.
1 is the only integer because 0.5 and 3/2 are not whole numbers and are fractions, while 1 is a whole number.
I only know 1 & 4 .. 2 & 3 seem hard to me ..
X >7
X< -7
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