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matrenka [14]
2 years ago
7

Find the volume of the cone shown below. 20 16 12

Mathematics
1 answer:
lina2011 [118]2 years ago
7 0
There is no picture but it’s 768 π
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While at the beach, daniel buys lunch for his family from a food stand. He purchased one hot dog for $2.50 and 3 hamburgers. If
ASHA 777 [7]

Answer:

Step-by-step explanation:

Let x represent the amount that he paid for one hamburger.

Daniel buys lunch for his family from a food stand. He purchased one hot dog for $2.50 and 3 hamburgers. The cost of 3 hamburgers would be 3x.

If he spent a total amount of $13 on the hot dog and hamburgers, it means that

2.5 + 3x = 13

3x = 13 - 2.5 = 10.5

x = 10.5/3

x = $3.5

7 0
4 years ago
A fish tank contains 16 goldfish and 24 guppies. If you randomly select 2 fish, what is the probability that they are both goldf
morpeh [17]
Hello, Shakiya214!

If a fish tank contains 16 goldfish and 24 guppies, then we can deduce that the total number of fish in the tank is: 16 + 24 = 40 fish.
If there are 16 goldfish in the tank, then of the 40 total fish, we have a probability of 16/40.

To illustrate this idea, suppose we had n fish in the tank (a guppies and b goldfish). The probability of selecting any fish is 100% (because there are only fish in the tank). If we had to select the goldfish, we could choose them like this:

p₁, p₂, p₃, p₄ ... pₐ

We could choose any one of these fish twice. This leaves us with: 16/40
Now, if they were NOT replaced, we could simply do it again. Except this time, we can only choose 15 out of the remaining 39 goldfish, leaving us with a probability of: (16/40)(15/39) = 240/1560 = 6/39 = 2/13
4 0
3 years ago
Read 2 more answers
What is the expanded notation fraction of 810.435
anygoal [31]

Answer:

800.000 + 10.000 + 0.000 + 0.400 + 0.030 + 0.005

6 0
3 years ago
Read 2 more answers
Find how many terms of a geometric progression 1+3+9 are required to make a total of more than 1 million.
Alborosie

The partial sum of a geometric sequence is

\displaystyle \sum_{i=0}^N a^i = \dfrac{a^{N+1}-1}{a-1}

In your case a=3, so if we sum N terms of the sequence we have

\displaystyle \sum_{i=0}^N 3^i = \dfrac{3^{N+1}-1}{2}

We want this to me more than 1 million, so we have

\dfrac{3^{N+1}-1}{2}>1000000 \iff 3^{N+1}-1>2000000 \iff 3^{N+1} > 1999999

Considering the log (base 3) of both sides, we have

N+1>\log_3(1999999)\iff N>\log_3(1999999)-1 approx 12.2

So, starting from N=13, the sum of the first N terms will be more than 1 million

3 0
4 years ago
Given that CB is tangent to A at C, then the value of X is
Marat540 [252]
Well just use the formula a^2+b^2=c^2. C squared in this case will be 30, It does not matter whether 24 is a or b^2 since we are still adding them. Now your equation should look like this

a^2+24=30 then….

a^2=30-24

a^2=6

a=square root of 6

Therefore your radius is square root of 6 or x=square root of 6
3 0
2 years ago
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