Each large box weighs 15 kilograms and each small box weighs 13.5 kilograms.
Step-by-step explanation:
Let,
Weight of large box = x
Weight of small box = y
According to given statement;
5x+2y=102 Eqn 1
3x+8y=153 Eqn 2
Multiyplying Eqn 1 by 4
Subtracting Eqn 2 from Eqn 3
Dividing both sides by 17
Putting x=15 in Eqn 2
Dividing both sides by 8
Each large box weighs 15 kilograms and each small box weighs 13.5 kilograms.
Keywords: linear equation, elimination method
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Answer:
−
3
−
9
n
Step-by-step explanation:
Simplify the expression
Answer:
16 cm
Step-by-step explanation:
Suppose that x is the original width. If that original width is enlarged by a scale factor 5/2 that means that x is multiplied by 5/2 and after that multiplication we obtained new width, 40 cm.
Therefore,
x*(5/2) = 40
We multiply the equation by 2 and obtain:
x*5 = 40*2
5x = 80
Now we divide the equation by 5 and obtain:
x = 80/5
x = 16
We obtained that x, the original width was 16 cm
Answer:
What shape is the object in question?
F(x)=x/6+2
There is no restriction upon the values of x, or the values of y.
So the domain and range are both the set of all real numbers.
x=(-oo, +oo) and y=(-oo, +oo)
This can be further seen by the fact that this is a line with a slope of 1/6. So there is no restriction upon x as all values of x produce real values of y. And y approaches -oo as x approaches -oo and y approaches +oo as x approaches +oo.
