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4vir4ik [10]
2 years ago
7

Hiii! Plzz help!

Mathematics
2 answers:
maksim [4K]2 years ago
8 0
1/6 of a minute is also 1/6*60 which equals to ten seconds. To find how many words she can type in 120 seconds, we need to divide 120 by 10 and then multiply the rate. 120/10 = 12, and then we multiply 12 by 8. 12*8=96
Firdavs [7]2 years ago
3 0

Answer:  

Hi! The answer is 96 words

Step-by-step explanation:

120 seconds = 2 minutes (120/60)

Minutes: 1/6 x 6 = 6/6 or 1 minute

Words: 8 x 6 =  48 words

so the rate is 48 words/per minute

48 x 2 = 96 words

1 x 2 =  2 minutes

<em>So she can type 96 words in 2 minutes/120 seconds</em>

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Which statement describes whether a right triangle can be formed using one side length from each of these squares?
balu736 [363]

Answer:

Step-by-step explanation:

The area of the given squares are

Area = 64 in

Area = 225 in

Area = 289 in

The length of each side of a square is determined by finding the square root of its area. For the first square, the length of its side is √64 = 8inches. For the second square, the length of its side is √225 = 15inches. For the third square, the length of its side is √289 = 17inches.

For a right angle triangle to be formed, Pythagorean theorem must be obeyed. Sum of the square of the smaller sides must equal the square of the longer side. Therefore,

8² + 15² = 17²

289 = 289

Therefore, the correct statement is

Yes, a right triangle can be formed because the sum of the areas of the two smaller squares equals the area of the largest square

4 0
3 years ago
0.376×800=(0.376×_____)×100 =______×100 =______
sergey [27]
0.376*800

=(0.376*8)*100

=3.008*100

=300.8
3 0
3 years ago
Look and solve plz herhenh
vodomira [7]

Answer:

s = 33

Step-by-step explanation:

99=3s

(99/3) = s

s=33

5 0
3 years ago
A sphere and a cylinder have the same radius and height. The volume of the cylinder is 18 cm.
Oksi-84 [34.3K]

Answer:

38cm3

Step-by-step explanation:

8 0
3 years ago
Use Fermat's Little Theorem to determine 7^542 mod 13.
m_a_m_a [10]

a^{p-1} \equiv 1 \pmod p where p is prime, a\in\mathbb{Z} and a is not divisible by p.

7^{13-1}\equiv 1 \pmod {13}\\7^{12}\equiv 1 \pmod {13}\\\\542=45\cdot12+2\\\\7^{45\cdot 12}\equiv 1 \pmod {13}\\7^{45\cdot 12+2}\equiv 7^2 \pmod {13}\\7^{542}\equiv 49 \pmod{13}

4 0
3 years ago
Read 2 more answers
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