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Nimfa-mama [501]
3 years ago
15

If you take out a $8,000 loan for a period of 6 months at an 8% interest rate, what will your outstanding balance be after two m

onthly payments? Round your answer to the nearest cent as necessary and do not include the dollar sign.
Mathematics
2 answers:
AysviL [449]3 years ago
8 0

Answer:

5,368.68

Step-by-step explanation:

the other answer was wrong this one correct

maksim [4K]3 years ago
4 0

Answer:

Outstanding balance after two months payments  = 7893.33

Step-by-step explanation:

Interest accrued every month = I = PRT/100

P = 8000

R = 8%

T = 6

I = (8000 x 8 x 6) ÷ 100 = 3840

Amount paid every month = (8000 + 3840) ÷ 6 = 1973.33

Hence amount paid after two months = 2 x 1973.33 = 3946.67

Outstanding balance after two months payments = 8000 +3840 - 3946.67 = 7893.33

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Which function is represented in this graph?
UNO [17]

Answer:

y = tan (1/2 x - π/2) ⇒ the answer is (b)

Step-by-step explanation:

* Lets talk about the tangent function

- The tangent has a period of π, with each period separated by

 a vertical asymptote. The concept of "amplitude" doesn't

  really exist because -∞ < y < ∞

- You can transform the graph for tangent

∵ y = A tan B(x + C) + D

* Where:

# A, changes amplitude. (A always = 1)

# B determines the period.

# C determines how the graph is shifted from left to right.

  (horizontally)

# D determines how the graph is shifted up or down.(vertically)

∵ The basic function is y = tanФ has an amplitude of 1.

   It has a period of π. It has no phase or vertical shifts,

   because it is centered on the origin.

* Look to the problem

- From the graph:

- The period is 2π

∵ Period = π/B

∴ 2π = π/B ⇒ ÷ π

∴ 2 = 1/B

∴ B = 1/2

- the starting point of the function is at π instead of zero

∴ It moves π units to the right

∴ C = -π

∴ y = tan 1/2(x - π)

∴ y = tan (1/2 x - π/2)

* The function is ⇒ y = tan (1/2 x - π/2)

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6 0
3 years ago
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WILL GIVE BRAINLIEST!
Nataly [62]

Answer:

The equation the circle is given by

{\bf 4x}^{\bf 2}+{\bf 4y}^{\bf 2}-{\bf 8x+0y-60}={\bf 0}

Step-by-step explanation:

The general form of the circle is

x^2+y^2+Dx+Ey+F=0\hfill (1)

Given points are (5,0) , (0,4) and (2,4)

Let the points (5,0) , (0,4) and (2,4) be (x_1,y_1) , (x_2,y_2) and (x_3,y_3) respectively

The equation of the circle passes through given points (5,0) , (0,4) and (2,4)

Substituting the point (5,0) in (1)

(-5)^2+(0)^2+D(5)+E(0)+F=0

25-5D+F=0

5D-F=25\hfill (2)

Substituting the point (0,4) in

(0)^2+(4)^2+D(0)+E(4)+F=0

16+4E+F=0

4E+F=-16\hfill (3)

Substituting the point (2,4) in

(2)^2+(4)^2+D(2)+E(4)+F=0

4+16+2D+4E+F=0

2D+4E+F=-20\hfill (4)

By solving the equations (2) ,(3) and(4) we get the values of D,E and F as below

D=-2  , E=0  and F=-15

substituting the values of D,E and F in (1) we get

x^2+y^2-2x+(0)y-15=0

Now multiplying the above equation into 4 we get

4x^2+4y^2-8x+(0)y-60=0

6 0
2 years ago
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