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posledela
2 years ago
9

A bullet with a mass of 14.5 is shot out of a rifle that has a length 1.08. The bullet spends 0.14 on the barreL. What is the ac

celeration as it travels through the barrel
Physics
1 answer:
Over [174]2 years ago
7 0

Answer:

110 m/s²

Explanation:

Given:

v₀ = 0 m/s

Δx = 1.08 m

t = 0.14 s

Find: a

Δx = v₀ t + ½ at²

1.08 m = (0 m/s) (0.14 s) + ½ a (0.14 s)²

a = 110 m/s²

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Two astronauts (each with mass 100 kg) are drifting together through space. They are connected to each other by a rope 5 m in le
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1000 kgm²/s, 400 J

1000 kgm²/s, 1000 J

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The rotational energy of the system is 400 J

There no external toque present so the initial and final angular momentum will be equal to the initial angular momentum 1000 kgm²/s

L_i=L_f\\\Rightarrow 2mv_ir_i=2mv_fr_f\\\Rightarrow v_f=\frac{v_ir_i}{r_f}\\\Rightarrow v_f=\frac{2\times 2.5}{0.5}\\\Rightarrow v_f=10\ m/s

Energy

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The work done is 600 J

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