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kifflom [539]
2 years ago
5

A Baker Had 1/3 Cups Of Suger . he Added 1/9 Cups To It Find The Total Number Of Sugar . ( Can Someone Help Me Out)

Mathematics
1 answer:
ella [17]2 years ago
3 0

The total number of sugar will be 9/4.

<h3>What is the unitary method?</h3>

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

A Baker Had 1/3 Cups Of Sugar.

he Added 1/9 Cups To It

Let the number of sugar be x

x (1/3)  + 1/9x = 1

3x + 1x = 9

4x = 9

x = 9/4

Hence, the total number of sugar will be 9/4.

Learn more about the unitary method;

brainly.com/question/23423168

#SPJ1

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Answer:

Solving the given linear system, we get x = 1 and y = -3.

The solution set is: (1,-3)

Step-by-step explanation:

We need to solve the linear system of equations.

3x-y=6 \\y=x-4

We can write second equation y=x-4  as: -x+y=-4

Let:

3x-y=6--eq(1)\\ -x+y=-4--eq(2)

Now, Adding equation 1 and 2

3x-y=6\\ -x+y=-4\\--------\\2x+0y=2\\2x=2\\x=\frac{2}{2}\\x=1

So, we get x = 1

Now, put value of x in second equation to find value of y:

y=x-4\\Put\:x=1\\y=1-4\\y=-3

So, we get y = -3

Solving the given linear system, we get x = 1 and y = -3.

The solution set is: (1,-3)

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3 years ago
What the next pattern of A, C, E, G, I
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Step-by-step explanation: A C E G I K M O Q S U W Y AA AC AE AG AI AK AO AQ AU AW AY BA

5 0
2 years ago
Select all the expressions that represent the large rectangle's total area.
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April sold 75 tickets to the school Christmas play and collected $495. If adult tickets cost $8 and children tickets were $5 how
Ostrovityanka [42]

40 adult tickets were sold and 35 children tickets were sold

<em><u>Solution:</u></em>

Let "a" be the number of adult tickets sold

Let "c" be the number of children tickets sold

Cost of 1 adult ticket = $ 8

Cost of 1 children ticket = $ 5

<em><u>Given that April sold 75 tickets to the school Christmas play and collected $495</u></em>

Number of tickets sold = 75

number of adult tickets sold + number of children tickets sold = 75

a + c = 75 ----- eqn 1

<em><u>Given that April collected $495</u></em>

Thus we can frame a equation as:

number of adult tickets sold x Cost of 1 adult ticket + number of children tickets sold x Cost of 1 children ticket = $ 495

a \times 8 + c \times 5 = 495

8a + 5c = 495 ----- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>

From eqn 1,

a = 75 - c ---- eqn 3

Substitute eqn 3 in eqn 2

8(75 - c) + 5c = 495

600 - 8c + 5c = 495

-3c = 495 - 600

-3c = - 105

<h3>c = 35</h3>

Substitute c = 35 in eqn 3

a = 75 - 35

<h3>a = 40</h3>

Thus 40 adult tickets were sold and 35 children tickets were sold

8 0
2 years ago
Lisa is in charge of planning a reception for 3600 people. She is trying to decide which snacks to buy. She has asked a random s
Olenka [21]

Answer:

The expected number of the people at the reception whose favorite snack will be chips is 1152

Step-by-step explanation:

Given

The data in the above table and

Reception = 3600

Required

Predict the number of the people at the reception whose favorite snack will be chips.

The first step is to determine the total number of samples;

Total = Brownies + Cookies + Chips + Other

Total = 32 + 22 + 56 + 65

Total = 175

The next step is to determine the fraction of people whose favorite is chips

Fraction = \frac{Chips}{Total}

Fraction = \frac{56}{175}

The product of the above fraction and the expected number of people in the reception is the solution to this question;

Expected\ Number = \frac{56}{175} * 3600

Expected\ Number = \frac{56* 3600}{175}

Expected\ Number = \frac{201600}{175}

Expected\ Number = 1152

<em>Hence, the expected number of the people at the reception whose favorite snack will be chips is 1152</em>

5 0
2 years ago
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