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Sliva [168]
2 years ago
6

What is the scale factor from the original design to the reduced design?

Mathematics
2 answers:
Vinil7 [7]2 years ago
8 0

Answer:

1/2

Step-by-step explanation:

uhh its 1/2

hodyreva [135]2 years ago
7 0

The original is 5 cm, the reduced image is 2.5

2.5/5 = 0.5 = 1/2

The scale for the reduced image is 1/2

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Write the equation of each ellipse in standard form with the given characteristics.
Eddi Din [679]

Answer:

Step-by-step explanation:

The foci are horizontally aligned.

horizontal ellipse:

(x-h)²/a² + (y-k)²/b² = 1

center (h,k)

vertices (h±a,k)

length of minor axis = 2b

foci (h±c,k), c² = a²-b²

Apply your data and solve for h, k, a, and b.

foci (±3√19, 6)

h = 0

k = 6

Length of minor axis = 2b = 10

b = 5

foci (h±3√19, 6)

c = 3√19

c³ = a² - b²

171 = a² - 25

a²  = 196

x²/196 + (y-6)²/25 = 1

6 0
2 years ago
Whats the distance between coordinates (-6,8) and (-6,-3)
insens350 [35]

Answer:

there away from eachother for 5 spaces.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A dartboard has a diameter of 18 inches.What are its radius and circumference?
allsm [11]
Diameter of the dartboard as given in the question = 18 inches
Then
Radius of the dartboard will be = 18/2 inches
                                                  = 9 inches
We already know that
Circumference of a circle = <span>2π</span>r
We also know that the value of <span>π = 3.14159
Then
Circumference of the dartboard = 2 * 3.14159 * 9 inches
                                                    = 56.548 inches
                                                    = 56.55 inches
So the radius of the dartboard is 9 inches and the circumference of the dartboard is 56.55 inches. I hope the procedure is absolutely clear to you.
</span>
3 0
3 years ago
Will give brainly if correct
LuckyWell [14K]

Answer: The answer is <u>7 1/3</u>

7 0
3 years ago
Question 19 of 28
Goryan [66]

Answer:

BC^2=10^2+30^2

Step-by-step explanation:

  • P=10
  • B=30

Using pythagorean theorem

\\ \sf\longmapsto BC^2=10^2+30^2

\\ \sf\longmapsto BC^2=100+300

\\ \sf\longmapsto BC^2=400

\\ \sf\longmapsto BC=\sqrt{400}

\\ \sf\longmapsto BC=20

8 0
2 years ago
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