3 years ago

Alguém me ajuda rapido por favor tou aki rachando a cuca e n consigo

Mathematics

1 answer:

Lady bird [3.3K]3 years ago

4 0

The vertices of a right triangle are (–6, 4), (0, 0), and (x, 0). Find the value of x.

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James says that 12 is a common factor of 3 and 4.june says that 12 is common multiple of 3 and 4.who is correct.

Sliva [168]

June is correct because 12 is a multiple of both 3 and 4.

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3 years ago

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Find the range of the data. 98, 21, 52, 39, 45 76

Alenkinab [10]

Answer:

Step-by-step explanation:

The range of the data is largest number minus smallest number.

98-21

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3 years ago

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Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v

k0ka [10]

I'll use subscript notation for brevity, i.e. $\frac{\partial f}{\partial x}=f_x$ .

By the chain rule,

$z_u=z_xx_u+z_yy_u$

$z_v=z_xx_v+z_yy_v$

$z_w=z_xx_w+z_yy_w$

We have

$z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}$

and

$\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}$

When $u=1,v=1,w=0$ , we have

$\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}$

and the partial derivatives take on values of

$\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}$

So we end up with

$\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}$

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Challenge A large university accepts 60% of the students who apply. Of the students the university

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Step-by-step explanation:

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2 years ago

I need sum help please and thanks :)

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