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Rama09 [41]
2 years ago
12

Area of a Square

Mathematics
1 answer:
Slav-nsk [51]2 years ago
8 0

The description of the area of a square is (c) as the length of the side increases, the area increases.

<h3>How to describe the area of a square?</h3>

The table of values is given as:

<u>Side Length (cm)        Area (cm²)</u>

1                                       1

2                                      4

3                                      9

4                                      16

5                                    25

In the above table, we can see that:

As length increases, the area also increases

Hence, the description of the area is (c) as the length of the side increases, the area increases.

Read more about areas at:

brainly.com/question/24487155

#SPJ1

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<h3>x = 1</h3>
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3 years ago
sam has to climb to the top of the building for his firefighter training. he doesn’t know how high it is. he is 6ft y’all and hi
Virty [35]

The height of building is 35 feet

<em><u>Solution:</u></em>

Given that,

Sam is 6 feet tall and his shadow is 3.6 feet tall

The shadow of building is 21 feet long

<em><u>To find: height of building</u></em>

We can solve this by setting up a ratio comparing the height of the building to the height of the Sam and shadow of the building to the shadow of the Sam

Let us consider,

h_b = height of building

h_m = height of Sam

s_b = shadow of building

s_m = shadow of Sam

Therefore,

\frac{\text {height of building}}{\text {shadow of building}}=\frac{\text {height of Sam}}{\text {shadow of Sam}}

\frac{h_{b}}{S_{b}}=\frac{h_{m}}{S_{m}}

Substitute the values,

\begin{aligned}&\frac{h_{b}}{21}=\frac{6}{3.6}\\\\&h_{b}=\frac{6}{3.6} \times 21\\\\&h_{b}=35\end{aligned}

Thus height of building is 35 feet

5 0
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1. BASEBALL For a particular baseball player, out of the
Dominik [7]

Answer:

No

Step-by-step explanation:

When using percentage out of a hundred, the number of percentage is the same number.

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6 0
3 years ago
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romanna [79]
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Solve the quadratic equation. Show all of your steps. x 2 + 3 x − 5 = 0
AlladinOne [14]

For this case we have the following quadratic equation:

x ^ 2 + 3x-5 = 0

Where:

a = 1\\b = 3\\c = -5

We look for the solution using the following formula:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

Substituting the values:

x = \frac {-3 \pm \sqrt {3 ^ 2-4 (1) (- 5)}} {2 (1)}\\x = \frac {-3 \pm \sqrt {9 + 20}} {2}\\x = \frac {-3 \pm \sqrt {29}} {2}

Thus, we have two roots:

x_ {1} = \frac {-3+ \sqrt {29}} {2}\\x_ {2} = \frac {-3- \sqrt {29}} {2}

Answer:

x_ {1} = \frac {-3+ \sqrt {29}} {2}\\x_ {2} = \frac {-3- \sqrt {29}} {2}

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