Answers:
1, It took him 21 minutes to reach the end.
2, He biked 8 kph/mph
3, He went 2.9 km/ 1.8 mi.
ur welcome
░░░░░▐▀█▀▌░░░░▀█▄░░░
░░░░░▐█▄█▌░░░░░░▀█▄░░
░░░░░░▀▄▀░░░▄▄▄▄▄▀▀░░
░░░░▄▄▄██▀▀▀▀░░░░░░
░░░█▀▄▄▄█░▀▀░░
░░░▌░▄▄▄▐▌▀▀▀░░ This is Bob
▄░▐░░░▄▄░█░▀▀ ░░
▀█▌░░░▄░▀█▀░▀ ░░ Copy and paste him so he can take over brainly.
░░░░░░░▀███▀█░▄░░
░░░░░░▐▌▀▄▀▄▀▐▄░░
░░░░░░▐▀░░░░░░▐▌░░
░░░░░░█░░░░░░░░█░
Answer:
128
Step-by-step explanation:
N(t) = 4(2)^t
N(t) = 4(2)^5
N(t) = 4(32)
N(t) = 128
Step-by-step explanation:
a I think if I didn't help sorry
Answer:
-9.5
Step-by-step explanation:
-4.75 = z/2
(2)-4.75 = (z/2) * (2)
-9.5 = z
So the question ask to find the displacement vector and the distance from the submarine to the boat. Base on my calculation the displacement value of the given data you give is <(5-3),(1-4)(-5-0)>. I hope you are satisfied with my answer and feel free to ask for more
