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Inessa05 [86]
3 years ago
11

A recipe for individual chocolate hazelnut tarts calls for ½ cup of hazelnuts per tart. If 1 cup of hazelnuts weighs 4 ounces, w

ill a 5-kilogram bag of hazelnuts be sufficient to make 75 tarts? 9.
Mathematics
1 answer:
DerKrebs [107]3 years ago
7 0

Answer:

The amount is sufficient to make 75 tarts.

Step-by-step explanation:

We have been given that a recipe for individual chocolate hazelnut tarts calls for ½ cup of hazelnuts per tart and 1 cup of hazelnuts weighs 4 ounces.

The half cup of hazelnuts will weigh 2 ounces (\frac{4}{2}=2).

1 kg equals 35.274 ounces.

\text{5 kg}=5\times 35.274\text{ ounces}

\text{5 kg}=176.37\text{ ounces}

Since each tart needs  ½ cup of hazelnuts and half cup of hazelnuts will weigh 2 ounces, so we will divide 176.37 ounces by 2 to find number of tarts.

\frac{176.37}{2}=88.185\approx 88

Since we can make 88 tarts from 5 kg hazelnuts, therefore, the 5-kilogram bag of hazelnuts be sufficient to make 75 tarts.

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One number is 8 times another number. The numbers are both positive and have a difference of 70. Find the numbers. Which of the
worty [1.4K]
Let, the first (smaller) number = x
Larger number = 8x
Then, 8x - x = 70
7x = 70
x = 70/7
x = 10
& 8(10) = 80

In short, Your Numbers would be, 10 & 80

Hope this helps!
4 0
3 years ago
Evaluate the expression (-3) 3
denis-greek [22]

Answer:

-9

Step-by-step explanation:

This is just -3 * 3

=-9

6 0
1 year ago
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Name the property 3. 7/9* 1= 7/9 ​
Nutka1998 [239]

Answer:

identify-multiplication

Step-by-step explanation:

anything you multiply by 1 is most likely going to be in the identify property

6 0
3 years ago
10. If 1000 cm = 1 l, find the capacity of the following water tank in litre
Lelu [443]
<h2>Given :</h2>

  • length = 200 cm

  • breadth = 150 cm

  • height = 100 cm

<h2>Solution : </h2>

\large \boxed{volume = l \times b \times h}

  • 200 \times 150 \times 100

  • 3000000  \: \: cm {}^{3}

Through the statement above we have,

  • \small\mathrm{1000  \: cm³ = 1  \:  \: }l

  • \small\mathrm{1 \: cm {}^{3}  =  \dfrac{1}{1000} \: }l

  • \small\mathrm{3000000 \: cm {}^{3}  = 3000000 \times  \dfrac{1}{1000}  \: }l

  • \small\mathrm{3000000 \: cm {}^{3}  = 3000000 \times  \dfrac{1}{1000}  \: }l

  • \small\mathrm{ 3000 \:  \: litres}

_____________________________

\mathrm{ \#TeeNForeveR}

3 0
3 years ago
The base of a circular fence with radius 10 m is given by x = 10 cost, y = 10 sin t. the height of the fence at position (x, y)
antiseptic1488 [7]

The parametric equations for x and y describe a circle of radius 10 m, so the length of the base of the fence is the length of the circumference of a circle of radius 10 m. The formula for that circumference (C) is ...

... C = 2πr

... C = 2π·(10 m) = 20π m

The height as a function of angle (t) is found by substituting for x and y.

... h(t) = h(x(t), y(t)) = 4 + 0.01·((10cos(t))²-)10sin(t))²) = 4+cos(2t)

The average value of this over the range 0 ≤ t ≤ 2π is 4, since the cosine function has two full cycles in that range, and its average value over a cycle is zero.

Thus, the area of one side of the fence is that of a rectangle 20π m long and 4 m wide. That will be

... (20π m)·(4 m) = 80π m²

The amount of paint required to cover both sides of the fence is

... 2×(80π m²)×(1 L)/(10 m²) = 16π L ≈ 50.3 L

_____

You can work out the integral for area as a function of t. When you do, you will find it gives this same result.

5 0
2 years ago
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